Civil Engineering - Theory of Structures - Discussion

Discussion Forum : Theory of Structures - Section 1 (Q.No. 5)
The normal component of a force inclined through θ° is obtained by multiplying the force by
sin θ
cos θ
tan θ
sin θ cos θ
Answer: Option
No answer description is available. Let's discuss.
13 comments Page 1 of 2.

Tark Raj Bhatt said:   11 months ago
I think it's sin^2 θ.

Yohannes said:   6 years ago
Does the inclination angle from horizontal or vertical?

Sheela said:   6 years ago
Thanks @Sanjay.

Keshav Raidas said:   6 years ago
Yes, right thanks @Sanjay.

Mokhtar said:   6 years ago
It will differ if the angles between the 3 directions are different.

Russ said:   6 years ago
What are the elements or components that involve in the study of the theory of structure?

Asaithambi said:   7 years ago
Horizontal vice force acting mention angle cosθ and vertical vice force acting mention angle is sinθ.

Sanjay said:   7 years ago
Let XY be the direction along which the given force is acting.

And we have to find the component of force in XZ direction.

It is given that the force is inclined at θ to the given plane (the plane is in between the XY and XZ line).

So component of F towards the given plane is F.Cosθ.

Now this F.Cosθ force is at an angle of (90-θ) to XZ.

Therefore its component towards XZ.

= F.Cosθ.Cos(90-θ).

= F.Cosθ.Sinθ.

Engr T Abioye said:   8 years ago
Sine θ is for the vertical i.e. normal and cos θ is for the horizontal components. If the angle of inclination is to the horizontal.

Raghuvesh tiwari said:   8 years ago
But both component will not be normal. So?

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