Discussion :: Theory of Structures  Section 1 (Q.No.5)
5. 
The normal component of a force inclined through θ° is obtained by multiplying the force by 
[A]. 
sin θ  [B]. 
cos θ  [C]. 
tan θ  [D]. 
sin θ cos θ  [E]. 
sin^{2}θ 
Answer: Option D
Explanation:
No answer description available for this question.

Gyanendra said:
(Dec 18, 2013)


Would you please let me know how it comes? I would be very grateful to you. 
Hanyibraheem said:
(Aug 18, 2014)


Sinθ for horizontal component and cosθ for vertical component. 
Sawan said:
(Oct 4, 2014)


Pleas tell me how it comes? 
Raghuvesh Tiwari said:
(Dec 3, 2014)


But both component will not be normal. So? 
Engr T Abioye said:
(Mar 25, 2015)


Sine θ is for the vertical i.e. normal and cos θ is for the horizontal components. If the angle of inclination is to the horizontal. 
Sanjay said:
(Jan 11, 2016)


Let XY be the direction along which the given force is acting.
And we have to find the component of force in XZ direction.
It is given that the force is inclined at θ to the given plane (the plane is in between the XY and XZ line).
So component of F towards the given plane is F.Cosθ.
Now this F.Cosθ force is at an angle of (90θ) to XZ.
Therefore its component towards XZ.
= F.Cosθ.Cos(90θ).
= F.Cosθ.Sinθ. 
Asaithambi said:
(Sep 21, 2016)


Horizontal vice force acting mention angle cosθ and vertical vice force acting mention angle is sinθ. 
Russ said:
(Jan 15, 2017)


What are the elements or components that involve in the study of the theory of structure? 
Mokhtar said:
(Mar 12, 2017)


It will differ if the angles between the 3 directions are different. 
Keshav Raidas said:
(Jun 9, 2017)


Yes, right thanks @Sanjay. 
Sheela said:
(Jul 23, 2017)


Thanks @Sanjay. 
Yohannes said:
(Sep 2, 2017)


Does the inclination angle from horizontal or vertical? 