Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 4)
4.
The combined effect of curvature and refraction over a distance L kilometres is
Discussion:
7 comments Page 1 of 1.
Sumeet kulkarni said:
8 years ago
Curvature correction = 0.0785D^2.
Refraction correction= 0.0785D^2÷7 = 0.0112D^2.
Combined correction = (0.0785-0.0112)D^2 =0.0672D^2.
Refraction correction= 0.0785D^2÷7 = 0.0112D^2.
Combined correction = (0.0785-0.0112)D^2 =0.0672D^2.
(3)
Kalpesh peshavariya said:
7 years ago
Thank you @Sumeet Kulkarni.
(1)
Shubash Sah said:
4 years ago
0.673d^2 where d is in km.
(1)
Dheeraj said:
6 years ago
@Sumit Kulkarni.
First, correct your calculations. (.0785-.0112=0.673).
Not (.0672).
And correct answer is, None of these, option D.
First, correct your calculations. (.0785-.0112=0.673).
Not (.0672).
And correct answer is, None of these, option D.
Xiyonee said:
5 years ago
@Dheeraj
That's not 0.673, It is 0.0673.
That's not 0.673, It is 0.0673.
Santosh ramani said:
3 years ago
Agree, Option A is correct.
Deepak raj joshi said:
2 months ago
The combined correction = 0.0673 L^2 meter.
where L is in Km.
where L is in Km.
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