Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 15)
15.
The sag of 50 m tape weighing 4 kg under 5 kg tension is roughly
Discussion:
24 comments Page 3 of 3.
JAY PANCHAL said:
8 years ago
In formula why you multiply 24 with 10^4?
Neelam said:
8 years ago
In formula why you multiply 24 with 10^4?
Harish said:
8 years ago
(LW^2/24*10^4)*P^2.
((50*4^2)/(24*10^4))*5^2 = 0.0833.
Ans is right.
((50*4^2)/(24*10^4))*5^2 = 0.0833.
Ans is right.
Rpy said:
8 years ago
The actual formula is LW^2/24p^2.
Where l is the length of tape, W=wl=weightt of tape in kg and p is pull. But it comes 1.33.
Where l is the length of tape, W=wl=weightt of tape in kg and p is pull. But it comes 1.33.
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