Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 15)
15.
The sag of 50 m tape weighing 4 kg under 5 kg tension is roughly
Discussion:
24 comments Page 2 of 3.
K Andres said:
1 year ago
I think this is the formula;
To get w = 4kg - 5kg = -1kg
Then p = 5
L = 50.
(1)^2(50)/24(5)^2 = 0.08333.
To get w = 4kg - 5kg = -1kg
Then p = 5
L = 50.
(1)^2(50)/24(5)^2 = 0.08333.
Sanku said:
5 years ago
Thanks @Johny Chauhan.
Adi said:
9 years ago
Anyone solve it.
Answer is not coming with formula w2l2/24p2.
Answer is not coming with formula w2l2/24p2.
RANJAN PATRA said:
9 years ago
It is LW2/24 * P2.
Rani said:
6 years ago
(5-4)^2*50/(24*5^2) = .0833.
Hasan said:
8 years ago
Please, someone explain it clearly, I am not getting the exact answer.
Prity said:
7 years ago
Why you multiplying with P^2 in W? Please explain the formula.
Madhukar said:
10 years ago
What is the formula was used for calculation?
Munesh kumar meena said:
7 years ago
Tell me the right formula.
Rafi said:
8 years ago
Can you please explain @ Harish, Why you multiplied 10^4 with 24?
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