Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 6 (Q.No. 15)
15.
The sag of 50 m tape weighing 4 kg under 5 kg tension is roughly
0.043 m
0.053 m
0.063 m
0.073 m
0.083 m
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
24 comments Page 2 of 3.

Sandeep said:   9 years ago
Please give the formula, to solve the question.

Sanku said:   5 years ago
Thanks @Johny Chauhan.

Adi said:   9 years ago
Anyone solve it.

Answer is not coming with formula w2l2/24p2.

RANJAN PATRA said:   9 years ago
It is LW2/24 * P2.

Rani said:   7 years ago
(5-4)^2*50/(24*5^2) = .0833.

Hasan said:   8 years ago
Please, someone explain it clearly, I am not getting the exact answer.

Prity said:   7 years ago
Why you multiplying with P^2 in W? Please explain the formula.

Madhukar said:   10 years ago
What is the formula was used for calculation?

Munesh kumar meena said:   8 years ago
Tell me the right formula.

Rafi said:   8 years ago
Can you please explain @ Harish, Why you multiplied 10^4 with 24?


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