Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 17)
17.
If 50 m point of a 100 m tape is 50 cm off line, and 50 m sections are straight, an error is generated equal to
.Discussion:
11 comments Page 1 of 2.
Muhammad Ashraf said:
9 years ago
Can any one explain?
Sundaes said:
9 years ago
Please explain it.
Nawa Raj Budha said:
9 years ago
Please explain the solution.
Samm said:
9 years ago
True length upto 50m portion is
√(50^2 + 0.5^2) = 50.0025.
So error is 50 - 50.025 = 0.025 m in 50 m length.
50 m length error is 0.025 m.
So in 100 m length error is 0.025 * 2 = 0.05 m,
So error is 0.05/100 = 1/20,000.
√(50^2 + 0.5^2) = 50.0025.
So error is 50 - 50.025 = 0.025 m in 50 m length.
50 m length error is 0.025 m.
So in 100 m length error is 0.025 * 2 = 0.05 m,
So error is 0.05/100 = 1/20,000.
M zahir said:
7 years ago
What is true length?
Lalit Roy said:
7 years ago
True length upto 50 m portion is √50^2+0.5^2 = 50.0025.
Error = 50.0025-50= 0.0025.
for 100 m length error = 0.0025*2=0.0050.
Error for 100 m= 0.005/100=1/20000.
Error = 50.0025-50= 0.0025.
for 100 m length error = 0.0025*2=0.0050.
Error for 100 m= 0.005/100=1/20000.
Anjana said:
6 years ago
Yes @lalit is right.
(1)
Yogi said:
6 years ago
The answer should be 1/40000.
For 50m length is 50.025,
And next 50 m is straight so it is 0.025/100.
For 50m length is 50.025,
And next 50 m is straight so it is 0.025/100.
(1)
Civima said:
4 years ago
Error =h^2/2*L.
For L= 50m and h= 0.5m , the error = 1/400.
Therefore error per unit length of 50m (as the rest part of the chain is straight) equals 1/(400*50) = 1/20,000.
For L= 50m and h= 0.5m , the error = 1/400.
Therefore error per unit length of 50m (as the rest part of the chain is straight) equals 1/(400*50) = 1/20,000.
(3)
John said:
4 years ago
Thanks @Civima.
(1)
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