Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 40)
40.
The bearings of the lines AB and BC are 146° 30' and 68° 30'. The included angle ABC is
Discussion:
40 comments Page 4 of 4.
Satyendra patel said:
10 years ago
180-146°30' + 68°30' = 102'.
PRAVESH VERMA said:
10 years ago
Both f.b.
So BC of B.B =68°30'+180° = 248°30'.
AB of f.b. = 146°30'.
/ABC = 248°30' - 146°30' = 102° answer.
So BC of B.B =68°30'+180° = 248°30'.
AB of f.b. = 146°30'.
/ABC = 248°30' - 146°30' = 102° answer.
Darshan H A said:
10 years ago
Included angle = Bearing of previous line - Bearing of next line
= bearing of ba - bearing of bc
= (180+146.5)-(68.5) = 258 which is exterior angle.
Hence interior angle = 360-258 = 102.
= bearing of ba - bearing of bc
= (180+146.5)-(68.5) = 258 which is exterior angle.
Hence interior angle = 360-258 = 102.
Darshik said:
10 years ago
146.5-90 = 56.5.
90-56.5 = 33.5.
33.5+68.5 = 102.
90-56.5 = 33.5.
33.5+68.5 = 102.
Chandan said:
1 decade ago
180°-146°30' = 33°30'.
68°30'+33°30' = 102°.
68°30'+33°30' = 102°.
Dhaval naam to suna hi hoga said:
1 decade ago
Simple 180-146°30'+78°30'=102.
Danesh said:
1 decade ago
Included angle = f.b of next line - b.b of previous line.
= f.b of BC - b.b of AB.
= 68.30 - 146.30.
= 78.
+180 = 102.
= f.b of BC - b.b of AB.
= 68.30 - 146.30.
= 78.
+180 = 102.
PRITHVEE RAJ said:
1 decade ago
INCLUDED ANGLE = 180'-146'30'+68'30' = 102'00'.
Pawan kumar said:
1 decade ago
146'30'-90' = 56'30.
90'-56'30' = 33'30+68'30 = 102'00'.
90'-56'30' = 33'30+68'30 = 102'00'.
Kala said:
1 decade ago
Answer: 146-68 = 78.
78+180 = 258.
360-258 = 102.
78+180 = 258.
360-258 = 102.
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