Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 40)
40.
The bearings of the lines AB and BC are 146° 30' and 68° 30'. The included angle ABC is
Discussion:
40 comments Page 3 of 4.
Leo said:
8 years ago
Great explanation @ Meghanada. Thanks.
Leo said:
8 years ago
Option d is right.
Becuase when bearing of two line measured not from their point of intersection. The rule of finding angle as different.
Becuase when bearing of two line measured not from their point of intersection. The rule of finding angle as different.
T vijay Bhaskar said:
8 years ago
Included angle =180-146°30'+68°30' = 102.
Er Meghanada said:
8 years ago
Force bearing of AB 146°30'.
Back Bearing of AB 146°30'+180°=326°30'.
Exterior angle ABC=B.B-BC.
=326°30'-68°30'=258°.
Interior angle ABC=360°-258°=102°.
Back Bearing of AB 146°30'+180°=326°30'.
Exterior angle ABC=B.B-BC.
=326°30'-68°30'=258°.
Interior angle ABC=360°-258°=102°.
Shashi said:
8 years ago
Yes, right @Chandan.
Sura said:
8 years ago
FB of AB 146°30'.
B. B. of AB 146°30'+180°=326°30'.
Exterior angle ABC=326°30'-68°30'=258°.
Interior angle ABC=360°-258°=102°.
B. B. of AB 146°30'+180°=326°30'.
Exterior angle ABC=326°30'-68°30'=258°.
Interior angle ABC=360°-258°=102°.
Pritam said:
8 years ago
But in book, Interior angle = BB of AB - FB of BC.
Are interior angle and included angle same.
Are interior angle and included angle same.
Sandip mondal said:
8 years ago
FB of AB=146°30'.
BB of AB=180°+146°30'=326°30.
Ext<ABC=326°30'-BB of BC=326°30'-68*30'=258°.
Int<ABC=360°-258°=102° ans.
BB of AB=180°+146°30'=326°30.
Ext<ABC=326°30'-BB of BC=326°30'-68*30'=258°.
Int<ABC=360°-258°=102° ans.
Indrajit Maiti said:
8 years ago
The bb of AB - fb of BC = {(180°+146°30')- 68°30'}= 258°,
Angle = (360°-258°) =102°.
Angle = (360°-258°) =102°.
Apurba said:
8 years ago
360 - (180 + 146°30) + 68°30 = 102.
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