# Civil Engineering - Surveying - Discussion

### Discussion :: Surveying - Section 1 (Q.No.40)

40.

The bearings of the lines AB and BC are 146° 30' and 68° 30'. The included angle ABC is

 [A]. 102° [B]. 78° [C]. 45° [D]. none of these.

Answer: Option A

Explanation:

No answer description available for this question.

 Kala said: (Aug 7, 2013) Answer: 146-68 = 78. 78+180 = 258. 360-258 = 102.

 Pawan Kumar said: (Nov 30, 2013) 146'30'-90' = 56'30. 90'-56'30' = 33'30+68'30 = 102'00'.

 PRITHVEE RAJ said: (Jan 23, 2014) INCLUDED ANGLE = 180'-146'30'+68'30' = 102'00'.

 Danesh said: (Jul 15, 2014) Included angle = f.b of next line - b.b of previous line. = f.b of BC - b.b of AB. = 68.30 - 146.30. = 78. +180 = 102.

 Dhaval Naam To Suna Hi Hoga said: (Jul 9, 2015) Simple 180-146°30'+78°30'=102.

 Chandan said: (Oct 4, 2015) 180°-146°30' = 33°30'. 68°30'+33°30' = 102°.

 Darshik said: (Dec 13, 2015) 146.5-90 = 56.5. 90-56.5 = 33.5. 33.5+68.5 = 102.

 Darshan H A said: (Dec 29, 2015) Included angle = Bearing of previous line - Bearing of next line = bearing of ba - bearing of bc = (180+146.5)-(68.5) = 258 which is exterior angle. Hence interior angle = 360-258 = 102.

 PRAVESH VERMA said: (Jan 25, 2016) Both f.b. So BC of B.B =68°30'+180° = 248°30'. AB of f.b. = 146°30'. /ABC = 248°30' - 146°30' = 102° answer.

 Satyendra Patel said: (Feb 26, 2016) 180-146°30' + 68°30' = 102'.

 Apurba said: (May 25, 2017) 360 - (180 + 146°30) + 68°30 = 102.

 Indrajit Maiti said: (Jul 24, 2017) The bb of AB - fb of BC = {(180°+146°30')- 68°30'}= 258°, Angle = (360°-258°) =102°.

 Sandip Mondal said: (Jul 31, 2017) FB of AB=146°30'. BB of AB=180°+146°30'=326°30. Ext

 Pritam said: (Aug 9, 2017) But in book, Interior angle = BB of AB - FB of BC. Are interior angle and included angle same.

 Sura said: (Aug 13, 2017) FB of AB 146°30'. B. B. of AB 146°30'+180°=326°30'. Exterior angle ABC=326°30'-68°30'=258°. Interior angle ABC=360°-258°=102°.

 Shashi said: (Sep 7, 2017) Yes, right @Chandan.

 Er Meghanada said: (Nov 12, 2017) Force bearing of AB 146°30'. Back Bearing of AB 146°30'+180°=326°30'. Exterior angle ABC=B.B-BC. =326°30'-68°30'=258°. Interior angle ABC=360°-258°=102°.

 T Vijay Bhaskar said: (Dec 5, 2017) Included angle =180-146°30'+68°30' = 102.

 Leo said: (Dec 22, 2017) Option d is right. Becuase when bearing of two line measured not from their point of intersection. The rule of finding angle as different.

 Leo said: (Dec 22, 2017) Great explanation @ Meghanada. Thanks.

 Apcivilian said: (Jan 5, 2018) Guys take as simple. ∠ABC = F.B of BC - B.B of AB = 68°30'- (146°30'+180°) = -258°. = -258° + 360°. = 102°. Hope it will help!

 Saurabh Kumar said: (Feb 25, 2018) As per my knowledge, Interior angle = BB of AB - FB of BC. Are interior angle and included angle same.

 Aadarsh Devkate said: (May 30, 2018) 180°-146°30°= 33°30°00°. So,

 Rakesh Kumar Baral said: (Sep 4, 2018) AB = 107*15'. BC= 22*00'. AB-BC= 107*15-22*00= 85*15'. Included angle ABC= 180*-85*15'= 94*45'.

 Shramik Shanti said: (Jan 11, 2019) Applying formula..Included angle = f.b of next line - b.b of previous line. = f.b of BC - b.b of AB. = 68.30 - 146.30. = 78. +180 = 102.

 KAN said: (Apr 6, 2019) BB of AB + FB of BC. BB of AB is 180-146.30 = 33.30, FB of BC is 68.30. So, 33.30 + 68.30 = 102.

 Mohmmed said: (Apr 14, 2019) The Azimuth of a line AB is 114 and the angle ABC 126°30'20". Calculate the Bearing of BC? Please answer this.

 Tarun Halder said: (Sep 6, 2019) Include angle b/w ABC = 108 - 146°30" + 68°30" = 102°.

 Sumit said: (Apr 26, 2020) In finding true angle (satellite station) reduction to center, then which formula is used? Please tell me.

 T.Aashish said: (Sep 6, 2020) Thanks for explaining @Meghanada.

 Mukesh Shah said: (Oct 6, 2020) Includes angle = fb of next line - bb of the previous line. = 68.30 - (146.30 + 180). = 63.38 - 326.30. = -258. Angel can not be negative so it will be added by 360. = -258 + 360. =102.

 Karan Yadav said: (Nov 26, 2020) 180 - 146 = 34. 34 + 68 = 102.

 Yojana said: (Mar 25, 2021) ∠ABC= BB-FB. 146 30 - 68 30 = 78. 180+78= 102°.

 Dipankar Barman said: (May 16, 2021) BB of AB - FB of BC (180° + 146°30') - 68°30' = 326°30'- 68°30'. = 258°(exterior angle), So included angle = 360°- 258°, = 102°.

 Prakash Singh Thakuri said: (Jun 26, 2021) (68°30' + 180°-146°30'. = 102°00'00".

 Bashant Khadka said: (Feb 20, 2022) 180-146°30'=33°3'; Include angle = 33°3`+68°3'= 102° Ans.

 Ramjan said: (Sep 11, 2022) Angle ABC= 360*(326°30'-68°30') =102°00'00" since this will be anti-clockwise so; Interior angle =360*[(BB)AB-(FB)BC].

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