Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 4 (Q.No. 47)
47.
The bearing of AB is 190° and that of CB is 260° 30'. The included angle ABC, is
Discussion:
13 comments Page 1 of 2.
Arindam said:
9 years ago
BB of AB is (190 - 180) = 10.
BB of CB = 260°30' - 180° = 80°30'.
Angle of ABC is 80°30' - 10° = 70°30'.
BB of CB = 260°30' - 180° = 80°30'.
Angle of ABC is 80°30' - 10° = 70°30'.
Chauhan munir said:
1 decade ago
BB of line AB = 190-180 = 10.
BB of line CB = 360-260 30' = 100 30'.
= 100 30'+10 = 110 30'.
= 180-110 30' = 70 30'.
BB of line CB = 360-260 30' = 100 30'.
= 100 30'+10 = 110 30'.
= 180-110 30' = 70 30'.
Umar habib said:
3 years ago
BB of line AB = 190-180 = 10.
BB of line CB = 360-260 30' = 100 30'.
= 100 30'+10 = 110 30'.
= 180-110 30' = 70 30'.
BB of line CB = 360-260 30' = 100 30'.
= 100 30'+10 = 110 30'.
= 180-110 30' = 70 30'.
(15)
Mirith said:
6 years ago
No @Chauhan Munir.
As per your calculation, BB of line CB = 360-260 30' = 99 30' (check properly).
As per your calculation, BB of line CB = 360-260 30' = 99 30' (check properly).
(1)
Vishvas said:
8 years ago
The included angle ABC = 260 30' - 190.
= 70°30'.
= 70°30'.
Brijesh said:
6 years ago
@Swapnil 80-10°30' = 69°30'
Your calculations are wrong.
Your calculations are wrong.
(2)
Karthik said:
6 years ago
The included angle ABC is 260°30'-190°=70°30'00''.
(3)
Dhiraj said:
5 years ago
@Subhankar.
You are absolutely right. Thanks for explaining.
You are absolutely right. Thanks for explaining.
(3)
Swapnil said:
8 years ago
AB=270-190=80.
BC=270-260.30=10.30.
Then 80-10.30=70.30.
BC=270-260.30=10.30.
Then 80-10.30=70.30.
Subhankar said:
5 years ago
(190*-180*)+(270*-260*30')+90*.
=10*+9*30'+90*.
109*30'.
=10*+9*30'+90*.
109*30'.
(3)
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