Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 4 (Q.No. 47)
47.
The bearing of AB is 190° and that of CB is 260° 30'. The included angle ABC, is
80° 30'
99° 30'
70° 30'
none of these
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Umar habib said:   1 year ago
BB of line AB = 190-180 = 10.
BB of line CB = 360-260 30' = 100 30'.
= 100 30'+10 = 110 30'.
= 180-110 30' = 70 30'.
(7)

Pronay said:   4 years ago
Right, Thanks @Subhankar.

Dhiraj said:   4 years ago
@Subhankar.

You are absolutely right. Thanks for explaining.
(1)

Subhankar said:   4 years ago
(190*-180*)+(270*-260*30')+90*.
=10*+9*30'+90*.
109*30'.
(2)

Brijesh said:   5 years ago
@Swapnil 80-10°30' = 69°30'

Your calculations are wrong.
(1)

Karthik said:   5 years ago
The included angle ABC is 260°30'-190°=70°30'00''.
(2)

Mirith said:   5 years ago
No @Chauhan Munir.

As per your calculation, BB of line CB = 360-260 30' = 99 30' (check properly).

Amu bokato said:   5 years ago
Thanks all for the explanation.
(1)

Athulya said:   6 years ago
Thank you for giving the explanation.

Swapnil said:   6 years ago
AB=270-190=80.
BC=270-260.30=10.30.
Then 80-10.30=70.30.


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