Civil Engineering - Surveying - Discussion

47. 

The bearing of AB is 190° and that of CB is 260° 30'. The included angle ABC, is

[A]. 80° 30'
[B]. 99° 30'
[C]. 70° 30'
[D]. none of these

Answer: Option C

Explanation:

No answer description available for this question.

Chauhan Munir said: (Apr 2, 2015)  
BB of line AB = 190-180 = 10.

BB of line CB = 360-260 30' = 100 30'.

= 100 30'+10 = 110 30'.

= 180-110 30' = 70 30'.

Arindam said: (Oct 3, 2016)  
BB of AB is (190 - 180) = 10.
BB of CB = 260°30' - 180° = 80°30'.
Angle of ABC is 80°30' - 10° = 70°30'.

Vishvas said: (May 21, 2017)  
The included angle ABC = 260 30' - 190.

= 70°30'.

Swapnil said: (Jan 20, 2018)  
AB=270-190=80.
BC=270-260.30=10.30.
Then 80-10.30=70.30.

Athulya said: (Sep 17, 2018)  
Thank you for giving the explanation.

Amu Bokato said: (Apr 14, 2019)  
Thanks all for the explanation.

Mirith said: (Jun 26, 2019)  
No @Chauhan Munir.

As per your calculation, BB of line CB = 360-260 30' = 99 30' (check properly).

Karthik said: (Oct 2, 2019)  
The included angle ABC is 260°30'-190°=70°30'00''.

Brijesh said: (Oct 15, 2019)  
@Swapnil 80-10°30' = 69°30'

Your calculations are wrong.

Subhankar said: (Mar 7, 2020)  
(190*-180*)+(270*-260*30')+90*.
=10*+9*30'+90*.
109*30'.

Dhiraj said: (Jul 7, 2020)  
@Subhankar.

You are absolutely right. Thanks for explaining.

Pronay said: (Aug 1, 2020)  
Right, Thanks @Subhankar.

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