Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 4 (Q.No. 8)
8.
ABCD is a rectangular plot of land. If the bearing of the side AB is 75°, the bearing of DC is
Discussion:
12 comments Page 1 of 2.
Shanky said:
8 years ago
AB 75°.
BC 75+90.
CD 75+90+90.
DC ..CD-180 =75°.
BC 75+90.
CD 75+90+90.
DC ..CD-180 =75°.
(8)
Ashok chauhan said:
4 years ago
Here's the answer.
Bearing of given line=FB of previous line+Included angle.
Then add or deduct 180.
So,
75 + 90(FB of pvs line) + 90(included angle) - 180 = 75.
Bearing of given line=FB of previous line+Included angle.
Then add or deduct 180.
So,
75 + 90(FB of pvs line) + 90(included angle) - 180 = 75.
(5)
Baloch said:
8 years ago
It's rectangular so back bearing of every point will be 255(75+180) and bearings will be 255-180 which is 75.
(2)
Nitin said:
9 years ago
@Shiv.
Because they ask DC not CD.
Because they ask DC not CD.
(1)
Bahada said:
9 years ago
How 75 is answer? Anyone explain.
(1)
Sonam Yeshay said:
7 years ago
Thanks for the explanation.
(1)
Gaye said:
4 years ago
Bearing 34-5.
= 29 because rectangular ABCD 29 * 2 = 58 + 17 = 75.
= 29 because rectangular ABCD 29 * 2 = 58 + 17 = 75.
(1)
Shiv said:
9 years ago
Why not option b?
Shaswata said:
7 years ago
Thanks @Shanky.
Lalit said:
6 years ago
Rectangular ABCD.
Bearing of line AB = Bearing of line DC.
75°=75°.
Bearing of line AB = Bearing of line DC.
75°=75°.
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