# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 4 (Q.No. 8)
8.
ABCD is a rectangular plot of land. If the bearing of the side AB is 75°, the bearing of DC is
75°
255°
105°
285°
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 1 of 2.

Ashok chauhan said:   3 years ago

Bearing of given line=FB of previous line+Included angle.
Then add or deduct 180.
So,
75 + 90(FB of pvs line) + 90(included angle) - 180 = 75.
(4)

Gaye said:   3 years ago
Bearing 34-5.
= 29 because rectangular ABCD 29 * 2 = 58 + 17 = 75.
(1)

Rohan Mukherjee said:   4 years ago
Thanks @Lalit.

Khait kanwal said:   4 years ago
This is the case of the rectangle so each BB of each corner would be the same as given 75 (Answer A is correct).

Lalit said:   4 years ago
Rectangular ABCD.
Bearing of line AB = Bearing of line DC.
75°=75°.

Shaswata said:   5 years ago
Thanks @Shanky.

Sonam Yeshay said:   6 years ago
Thanks for the explanation.
(1)

Shanky said:   7 years ago
AB 75°.
BC 75+90.
CD 75+90+90.
DC ..CD-180 =75°.
(5)

Baloch said:   7 years ago
It's rectangular so back bearing of every point will be 255(75+180) and bearings will be 255-180 which is 75.
(2)

Bahada said:   7 years ago
How 75 is answer? Anyone explain.
(1)