# Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 4 (Q.No. 8)

8.

*ABCD*is a rectangular plot of land. If the bearing of the side

*AB*is 75°, the bearing of

*DC*is

Discussion:

12 comments Page 1 of 2.
Ashok chauhan said:
3 years ago

Here's the answer.

Bearing of given line=FB of previous line+Included angle.

Then add or deduct 180.

So,

75 + 90(FB of pvs line) + 90(included angle) - 180 = 75.

Bearing of given line=FB of previous line+Included angle.

Then add or deduct 180.

So,

75 + 90(FB of pvs line) + 90(included angle) - 180 = 75.

(4)

Gaye said:
3 years ago

Bearing 34-5.

= 29 because rectangular ABCD 29 * 2 = 58 + 17 = 75.

= 29 because rectangular ABCD 29 * 2 = 58 + 17 = 75.

(1)

Rohan Mukherjee said:
4 years ago

Thanks @Lalit.

Khait kanwal said:
4 years ago

This is the case of the rectangle so each BB of each corner would be the same as given 75 (Answer A is correct).

Lalit said:
4 years ago

Rectangular ABCD.

Bearing of line AB = Bearing of line DC.

75°=75°.

Bearing of line AB = Bearing of line DC.

75°=75°.

Shaswata said:
5 years ago

Thanks @Shanky.

Sonam Yeshay said:
6 years ago

Thanks for the explanation.

(1)

Shanky said:
7 years ago

AB 75°.

BC 75+90.

CD 75+90+90.

DC ..CD-180 =75°.

BC 75+90.

CD 75+90+90.

DC ..CD-180 =75°.

(5)

Baloch said:
7 years ago

It's rectangular so back bearing of every point will be 255(75+180) and bearings will be 255-180 which is 75.

(2)

Bahada said:
7 years ago

How 75 is answer? Anyone explain.

(1)

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