Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 10)
10.
If the whole circle bearing of a line is 270°, its reduced bearing is
Discussion:
35 comments Page 3 of 4.
Baloch said:
9 years ago
Yes @Irfan,
It's in 3rd quadrant, so, the answer is [B] i.e. S90°W.
It's in 3rd quadrant, so, the answer is [B] i.e. S90°W.
Vinod said:
9 years ago
How, Can anyone explain it?
Rakesh said:
8 years ago
Clear between w90 or 90w?
Santhosh said:
8 years ago
Answer is option B. So 90 degree W.
MLY said:
8 years ago
I think the answer is 90° W.
Dev said:
8 years ago
Answer should be D.
Umashanker said:
8 years ago
Answer should be options B.
Binesh said:
6 years ago
You are right, thanks @Jayraj.
Amexo said:
7 years ago
As per my knowledge, N 90° W is the answer.
Rohit said:
7 years ago
360-270=90.
As the 270 lies on exact quadrant line i.e 270.
So it is W only, not even in third and fourth quadrant.
Hence, option C and D are correct.
As the 270 lies on exact quadrant line i.e 270.
So it is W only, not even in third and fourth quadrant.
Hence, option C and D are correct.
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