Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 10)
10.
If the whole circle bearing of a line is 270°, its reduced bearing is
Discussion:
34 comments Page 3 of 4.
Jayraj Khatri said:
7 years ago
Answer is C
If you see from both references N and S than it is same so confusion occurs.
If you write 90 W then it will be same as showing declination.
Due to this, all reason at this point answer is W 90.
Similarly,
0° = N 0,
180° = S 0,
90° = E 90,
270° = W 90.
If you see from both references N and S than it is same so confusion occurs.
If you write 90 W then it will be same as showing declination.
Due to this, all reason at this point answer is W 90.
Similarly,
0° = N 0,
180° = S 0,
90° = E 90,
270° = W 90.
Narayan said:
7 years ago
The answer will be 90° west.
Surojit said:
7 years ago
@Prudhvi.
359°= N1°W.
And 181°=S1°W.
359°= N1°W.
And 181°=S1°W.
Rohit said:
7 years ago
360-270=90.
As the 270 lies on exact quadrant line i.e 270.
So it is W only, not even in third and fourth quadrant.
Hence, option C and D are correct.
As the 270 lies on exact quadrant line i.e 270.
So it is W only, not even in third and fourth quadrant.
Hence, option C and D are correct.
Amexo said:
7 years ago
As per my knowledge, N 90° W is the answer.
Shiv kumar said:
7 years ago
I think both A and B is the right answer.
Umashanker said:
8 years ago
Answer should be options B.
Dev said:
8 years ago
Answer should be D.
MLY said:
8 years ago
I think the answer is 90° W.
Santhosh said:
8 years ago
Answer is option B. So 90 degree W.
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