Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 7 (Q.No. 10)
10.
If the whole circle bearing of a line is 270°, its reduced bearing is
N 90° W
S 90° W
W 90°
90° W.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
34 comments Page 2 of 4.

Umesh said:   5 years ago
Answer should be (B) because W. C. B is in third quadrant so S 90° W.
(1)

Baloch said:   9 years ago
Yes @Irfan,

It's in 3rd quadrant, so, the answer is [B] i.e. S90°W.

Irfan ahmad lone said:   1 decade ago
The answer is S 90 degree W because it lies in third quadrant.

Prudhvi said:   8 years ago
What if W.C.B is 359, what is R.B? PLease anyone answer me.
(1)

Umair said:   5 years ago
R.b is equal to WCB in which quadrant? Can anyone tell me?
(1)

Nagababu said:   10 years ago
Then it can be of N 90 degree W.

So answer is west 90.

Surojit said:   7 years ago
@Prudhvi.

359°= N1°W.
And 181°=S1°W.

Amexo said:   7 years ago
As per my knowledge, N 90° W is the answer.

Shiv kumar said:   7 years ago
I think both A and B is the right answer.

Santhosh said:   8 years ago
Answer is option B. So 90 degree W.


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