Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 7 (Q.No. 10)
10.
If the whole circle bearing of a line is 270°, its reduced bearing is
Discussion:
33 comments Page 2 of 4.
Shiv kumar said:
7 years ago
I think both A and B is the right answer.
Amexo said:
6 years ago
As per my knowledge, N 90° W is the answer.
Rohit said:
6 years ago
360-270=90.
As the 270 lies on exact quadrant line i.e 270.
So it is W only, not even in third and fourth quadrant.
Hence, option C and D are correct.
As the 270 lies on exact quadrant line i.e 270.
So it is W only, not even in third and fourth quadrant.
Hence, option C and D are correct.
Surojit said:
6 years ago
@Prudhvi.
359°= N1°W.
And 181°=S1°W.
359°= N1°W.
And 181°=S1°W.
Narayan said:
6 years ago
The answer will be 90° west.
Jayraj Khatri said:
6 years ago
Answer is C
If you see from both references N and S than it is same so confusion occurs.
If you write 90 W then it will be same as showing declination.
Due to this, all reason at this point answer is W 90.
Similarly,
0° = N 0,
180° = S 0,
90° = E 90,
270° = W 90.
If you see from both references N and S than it is same so confusion occurs.
If you write 90 W then it will be same as showing declination.
Due to this, all reason at this point answer is W 90.
Similarly,
0° = N 0,
180° = S 0,
90° = E 90,
270° = W 90.
Abu said:
6 years ago
A is the right answer.
Gorishankar said:
5 years ago
N90W and S90W both are correct.
Binesh said:
5 years ago
You are right, thanks @Jayraj.
Venkat said:
5 years ago
Correct @Jayraj.
Because in reduced bearings are done by surveyor compass.
S = 0.
W = 90.
N = 0.
E = 90.
Because in reduced bearings are done by surveyor compass.
S = 0.
W = 90.
N = 0.
E = 90.
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