Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 14)
14.
If the length of a chain line along a slope of θ° is l, the required slope correction is
Discussion:
9 comments Page 1 of 1.
Rahul said:
4 years ago
Slope correction= L(1-cosθ).
Then multiplying & divided by 2;
2L(1-cosθ)/2.
Where (1-cosθ)/2 = sin^2(θ/2).
Then 2Lsin^2(θ/2).
Then multiplying & divided by 2;
2L(1-cosθ)/2.
Where (1-cosθ)/2 = sin^2(θ/2).
Then 2Lsin^2(θ/2).
Pkota said:
4 years ago
Correct answer l(sin@)^2.
As given l is length along scope so;
(hypotaneous=l),
Height h= l sin@,
Scope correction = h^2/2l = (l sin@)^2/2l.
= {l (sin@)^2}/2.
As given l is length along scope so;
(hypotaneous=l),
Height h= l sin@,
Scope correction = h^2/2l = (l sin@)^2/2l.
= {l (sin@)^2}/2.
(2)
Silpa said:
5 years ago
Please explain clearly to get the answer.
(1)
Tenu said:
5 years ago
Please give a correct explanation.
Pallavi sharma said:
5 years ago
Cv= L-Lcos θ.
= L ( 1-cosθ ). (1-cosθ )= 2sin^2(θ/2).
= 2L sin^2 (θ/2). Slope correction is H^2/2L.
= L ( 1-cosθ ). (1-cosθ )= 2sin^2(θ/2).
= 2L sin^2 (θ/2). Slope correction is H^2/2L.
Gyana said:
5 years ago
No. The answer should be Lsin2@/2. Because slope correction=h2/2L. And h=LSin @.
(1)
P raj said:
7 years ago
Please give an explanation.
Yamini Dewangan said:
8 years ago
Correction for slope in terms of angle can be;
C =L- Lcosx =2Lsin^2x/2.
C =L- Lcosx =2Lsin^2x/2.
Divyang said:
8 years ago
Can anyone explain this?
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