Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 42)
42.
The slope correction for a length of 30 m along a gradient of 1 in 20, is
Discussion:
58 comments Page 5 of 6.
Sanjukta said:
9 years ago
Thank you for the explanation friends.
Nawa Raj Budha said:
9 years ago
Good explanations friends. Thank you.
Baloch said:
9 years ago
Slope correction = h^2 / 2l.
h = 20/30 = 1.5.
l = length.
By submitting the value you will get the answer.
h = 20/30 = 1.5.
l = length.
By submitting the value you will get the answer.
MD FAISAL said:
9 years ago
In ABC triangle,
AC = l = 30m.
Slope = 1 : 20.
1 in20 so in 30 = (1/20) * 30 = 1.5
Therefore BC = 1.5m.
And AB extends to BB'.
And meet to points A as arc & B as a straight line.
Here BB'= correction of line,
= AC - AB.
AB = (30^2 - 1.5^2)^1/2
= 29.962m.
BB' = 30 - 29.962
= 0.0375m or 3.75cm.
AC = l = 30m.
Slope = 1 : 20.
1 in20 so in 30 = (1/20) * 30 = 1.5
Therefore BC = 1.5m.
And AB extends to BB'.
And meet to points A as arc & B as a straight line.
Here BB'= correction of line,
= AC - AB.
AB = (30^2 - 1.5^2)^1/2
= 29.962m.
BB' = 30 - 29.962
= 0.0375m or 3.75cm.
Hima Bindu said:
9 years ago
How h =1.5?
Swamy said:
9 years ago
Hi, friends all give the good explanations. Thank you.
Ali said:
9 years ago
We know for 30 m length, h = 1.5
And given gradient is 1 in 20 i.e 1/20
So, the equation of slope correction is,
= h^2 / 2l
= 1.5^2 / 2*30 m
= 2.25 / 60m
= 0.0375 m or 3.75 cm
And given gradient is 1 in 20 i.e 1/20
So, the equation of slope correction is,
= h^2 / 2l
= 1.5^2 / 2*30 m
= 2.25 / 60m
= 0.0375 m or 3.75 cm
Kanhu said:
1 decade ago
Slope correction for a sloping ground = h^2/2l.
Where h = height.
l = length of the ground.
Where h = height.
l = length of the ground.
Maheshkumar said:
1 decade ago
In 1 in 20 means, 20m = 1m.
So total 30m length = 1.5m.
In Gradient 1 in 20 Means.
Imagine Triangle, length-30m & Height-1.5m.
Use Pythagoras theorem.
X2 = 302+1.52.
X = 30.0375m.
Change length = 30.0375-30.
= 0.0375m.
= 3.75cm.
So total 30m length = 1.5m.
In Gradient 1 in 20 Means.
Imagine Triangle, length-30m & Height-1.5m.
Use Pythagoras theorem.
X2 = 302+1.52.
X = 30.0375m.
Change length = 30.0375-30.
= 0.0375m.
= 3.75cm.
Engr Attaullah Khan Tareen said:
1 decade ago
For 20 m, h = 1 m. So for 30 m, h = 1.5 m.
So that = h^2/2l = (1.5) 2/2*30 = 0.0375 m.
1 m = 100 cm so 0.0375*100 = 3.75 cm.
So that = h^2/2l = (1.5) 2/2*30 = 0.0375 m.
1 m = 100 cm so 0.0375*100 = 3.75 cm.
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