Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 1 (Q.No. 42)
42.
The slope correction for a length of 30 m along a gradient of 1 in 20, is
Discussion:
58 comments Page 4 of 6.
Pranab said:
1 decade ago
h = 1.5 m & l = 30 m.
So that = h2/2l = (1.5)2/2*30 = 0.0375 cm.
So that = h2/2l = (1.5)2/2*30 = 0.0375 cm.
Ankit said:
6 years ago
Slope correction is negative or positive? Give details about it.
Charan Singh Majhi said:
6 years ago
Slope correction = h^2/2l = 1.5^2/2*30 = 0.0375mtr = 3.75cm.
Adarsh Krishna said:
5 years ago
h^2/2l = 1.5*1.5/(2*30) = .0375m its change cm. = 3.75cm
(1)
Swamy said:
9 years ago
Hi, friends all give the good explanations. Thank you.
Ritesh Kumar singh said:
6 years ago
Thanks for the explanation @Shubhajit Chakrabarty.
Rasheedrash79 said:
7 years ago
How are they getting 1.5*2=2.25? Please explain.
Kiran said:
7 years ago
Thank you all for explaining the solution.
Anil soni said:
1 decade ago
For 20 m, h = 1 m. So for 30 m, h = 1.5 m.
Sanjukta said:
9 years ago
Thank you for the explanation friends.
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