Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 1 (Q.No. 42)
42.
The slope correction for a length of 30 m along a gradient of 1 in 20, is
3.75 cm
0.375 cm
37.5 cm
2.75 cm.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
58 comments Page 3 of 6.

Karn chaurasiya said:   6 years ago
150/ n^2 because 30 metre chain used and now slope current is 150/ 20^2 = 150 ÷ 400 = 0.375 m or 3. 75 cm.

Baloch said:   9 years ago
Slope correction = h^2 / 2l.
h = 20/30 = 1.5.
l = length.
By submitting the value you will get the answer.

Sameer sopori said:   7 years ago
h^2/2L.

h= 1.5 (because of 1:20, 1/20 * 30 = 1.5),
h= 2.25/60,
h= 0.375m,
h= 0.375 * 100,
h= 3.75cm.

Avinash said:   12 months ago
For Determining H = 20/30 = 1.5
The formula for slope H^2/2L.
L = 30.
1.5^2/2×30 = 0.0375 × 100 = 3.75cm.

Gulshan Kumar said:   7 years ago
But 30 M is along the gradient, not horizontal distance.

So, the value of h won't be exactly 1.5 M.

Manoj said:   7 years ago
By using of similarity of the triangle.

H = 30÷401 and putting into slope correction formula.

Kanhu said:   1 decade ago
Slope correction for a sloping ground = h^2/2l.

Where h = height.

l = length of the ground.

Sandeep said:   1 decade ago
(1.5)2 / 2x3000 = 3.75 cm.

Note: Length 30 m, gradient 1/20 ; h= 1.5.

Equation : h2/2l.

Asad Ali Chandia said:   8 years ago
Slop correction Formula = h^2/2*L.
h = 30*(1/20) = 1.5
Hence, correction = 3.375 cm.

Bhupendra murariya said:   9 years ago
Not understanding, Please give the correct explanation for this question.


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