Civil Engineering - Surveying - Discussion

Discussion Forum : Surveying - Section 7 (Q.No. 24)
24.
The correction to be applied to each 30 metre chain length along θ° slope, is
30 (sec θ - 1) m
30 (sin θ - 1) m
30 (cos θ - 1) m
30 (tan θ - 1) m
30 (cot θ - 1) m.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
26 comments Page 3 of 3.

Akash said:   8 years ago
Actual slope correction is always -ve therefore, Correction = -[L(1-cosX)].
=(LcosX-L).
=L(cosX-1) ; now L is 30m chain.
So the answer comes out to be;
=30(cosX-1) m.

Nikhitha said:   8 years ago
How A will be correct?

I think C is correct.

Ajaynakum said:   8 years ago
Slope correction = L (1-cosθ).
Then A is correct answer.

Manish said:   8 years ago
The correct answer is Angle with θ l (1-cosθ).

Dilip said:   8 years ago
Slope correction is = L(cosθ-1).

Can you explain how this is wrong?

Prashant said:   8 years ago
Anyone explain this answer.


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