Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 8)
8.
The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only
Discussion:
45 comments Page 3 of 5.
Eva said:
6 years ago
The answer should be 1.5 cm.
Nayeem said:
4 years ago
Please explain the right answer.
Raj Kumar said:
4 years ago
Please explain the right answer.
Nitish Mahato said:
6 months ago
10 cm in a length of 18.2 Km.
30 cm in a length of 54.5 km.
50 cm in a length of 91 km.
30 cm in a length of 54.5 km.
50 cm in a length of 91 km.
Nayan ahir said:
8 years ago
For 18.2km - 0.1m=10cm,
For 54.3km- 0.3m=30cm,
For 91km- 0.5m=50cm.
For 54.3km- 0.3m=30cm,
For 91km- 0.5m=50cm.
Ashu said:
9 years ago
@Raihan.
Number of the difference between the arc length and its subtended chord on the earth surface for a distance of 18.2 km is 0.1 m. So the correct option is (c) 10 cm.
Number of the difference between the arc length and its subtended chord on the earth surface for a distance of 18.2 km is 0.1 m. So the correct option is (c) 10 cm.
Shyam lal yadav said:
9 years ago
0.1 m so 10 cm.
Sohel said:
9 years ago
But in a book of surveying, the difference is 1cm for 12 km distance so how it is possible to 10 cm for 18.2 km? As per book answer will be 1.5 cm.
Engr said:
8 years ago
I think units are in mm not cm.
It's 10mm not 10cm.
It's 10mm not 10cm.
Ashu said:
8 years ago
10mm = 1 cm is the correct answer.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers