Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 8)
8.
The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only
Discussion:
45 comments Page 2 of 5.
Raihan said:
1 decade ago
For 12 km the difference = 1 cm.
So for 18.2 km = 18. 2-1/12 = 1.52 cm = 15 mm.
So for 18.2 km = 18. 2-1/12 = 1.52 cm = 15 mm.
(1)
A k singh said:
7 years ago
It should be 10mm.
(1)
Santosh Neelannavar said:
7 years ago
The correct answer 10cm.
18.2km =0.1m.
54.3km = 0.3m.
90km = 0.5m.
18.2km =0.1m.
54.3km = 0.3m.
90km = 0.5m.
(1)
Rakesh Kumar Chhalotre said:
7 years ago
12km - 1cm.
So, for 18.2km - 1.5cm = 15mm is correct.
So, for 18.2km - 1.5cm = 15mm is correct.
(1)
JEET said:
6 years ago
For distance upto 18.2 km is 10 cm.
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.
Ref: RS Khurmi(clause 5.1)
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.
Ref: RS Khurmi(clause 5.1)
(1)
Bhupesh said:
6 years ago
10mm is correct.
Badal kumar said:
6 years ago
10mm is the correct Answer.
SUDHEESHBABU said:
6 years ago
The answer was 0.1m for 18.2km.
Acc to surveying and leveling by kanetkar page no. 3.
I'm very sure. So don't study other values.
Acc to surveying and leveling by kanetkar page no. 3.
I'm very sure. So don't study other values.
Dhanaraj said:
6 years ago
How to find an answer for this? Please tell me.
Shivam said:
5 years ago
I am not getting this. Please explain in detail.
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