Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 8)
8.
The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only
Discussion:
45 comments Page 2 of 5.
Raihan said:
1 decade ago
For 12 km the difference = 1 cm.
So for 18.2 km = 18. 2-1/12 = 1.52 cm = 15 mm.
So for 18.2 km = 18. 2-1/12 = 1.52 cm = 15 mm.
(1)
Santosh Neelannavar said:
7 years ago
The correct answer 10cm.
18.2km =0.1m.
54.3km = 0.3m.
90km = 0.5m.
18.2km =0.1m.
54.3km = 0.3m.
90km = 0.5m.
(1)
JEET said:
6 years ago
For distance upto 18.2 km is 10 cm.
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.
Ref: RS Khurmi(clause 5.1)
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.
Ref: RS Khurmi(clause 5.1)
(1)
Rakesh Kumar Chhalotre said:
8 years ago
12km - 1cm.
So, for 18.2km - 1.5cm = 15mm is correct.
So, for 18.2km - 1.5cm = 15mm is correct.
(1)
Engr said:
9 years ago
I think units are in mm not cm.
It's 10mm not 10cm.
It's 10mm not 10cm.
(1)
Nitish Mahato said:
1 year ago
10 cm in a length of 18.2 Km.
30 cm in a length of 54.5 km.
50 cm in a length of 91 km.
30 cm in a length of 54.5 km.
50 cm in a length of 91 km.
(1)
Badal kumar said:
6 years ago
10mm is the correct Answer.
Bhupesh said:
6 years ago
10mm is correct.
Shivam said:
5 years ago
I am not getting this. Please explain in detail.
Nayeem said:
5 years ago
Please explain the right answer.
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