Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 8)
8.
The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only
Discussion:
45 comments Page 2 of 5.
Santosh Neelannavar said:
6 years ago
The correct answer 10cm.
18.2km =0.1m.
54.3km = 0.3m.
90km = 0.5m.
18.2km =0.1m.
54.3km = 0.3m.
90km = 0.5m.
(1)
A k singh said:
6 years ago
It should be 10mm.
(1)
Raihan said:
1 decade ago
For 12 km the difference = 1 cm.
So for 18.2 km = 18. 2-1/12 = 1.52 cm = 15 mm.
So for 18.2 km = 18. 2-1/12 = 1.52 cm = 15 mm.
(1)
Pradeep Kumar Yadav said:
6 years ago
1 cm =10 mm is the correct answer.
(1)
Sami said:
6 years ago
It should be 10mm.
Ref: Khurmi.
Ref: Khurmi.
Dhanaraj said:
6 years ago
How to find an answer for this? Please tell me.
Shivam said:
5 years ago
I am not getting this. Please explain in detail.
SUDHEESHBABU said:
6 years ago
The answer was 0.1m for 18.2km.
Acc to surveying and leveling by kanetkar page no. 3.
I'm very sure. So don't study other values.
Acc to surveying and leveling by kanetkar page no. 3.
I'm very sure. So don't study other values.
Bhupesh said:
5 years ago
10mm is correct.
Badal kumar said:
5 years ago
10mm is the correct Answer.
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