Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 8)
8.
The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only
Discussion:
45 comments Page 1 of 5.
Raihan said:
1 decade ago
For 12 km the difference = 1 cm.
So for 18.2 km = 18. 2-1/12 = 1.52 cm = 15 mm.
So for 18.2 km = 18. 2-1/12 = 1.52 cm = 15 mm.
(1)
Ashu said:
9 years ago
@Raihan.
Number of the difference between the arc length and its subtended chord on the earth surface for a distance of 18.2 km is 0.1 m. So the correct option is (c) 10 cm.
Number of the difference between the arc length and its subtended chord on the earth surface for a distance of 18.2 km is 0.1 m. So the correct option is (c) 10 cm.
Shyam lal yadav said:
9 years ago
0.1 m so 10 cm.
Sohel said:
9 years ago
But in a book of surveying, the difference is 1cm for 12 km distance so how it is possible to 10 cm for 18.2 km? As per book answer will be 1.5 cm.
Engr said:
8 years ago
I think units are in mm not cm.
It's 10mm not 10cm.
It's 10mm not 10cm.
Ashu said:
8 years ago
10mm = 1 cm is the correct answer.
ARVIND said:
8 years ago
IT SHOULD BE 15mm.
For 12km=10mm (as per BC PUNMIA).
So,for 18.2 km = 15mm.
For 12km=10mm (as per BC PUNMIA).
So,for 18.2 km = 15mm.
Naveen said:
8 years ago
The correct answer must 15mm.
Avinash Gund said:
8 years ago
For 18.2 km 10 mm is correct.
For 18.5km 15 mm is correct.
For 18.5km 15 mm is correct.
Angel said:
8 years ago
I think, 10mm is correct.
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