Civil Engineering - Surveying - Discussion
Discussion Forum : Surveying - Section 6 (Q.No. 8)
8.
The difference in the lengths of an arc and its subtended chord on the earth surface for a distance of 18.2 km, is only
Discussion:
45 comments Page 2 of 5.
Gaurav said:
8 years ago
10 mm is correct.
Nayan ahir said:
8 years ago
For 18.2km - 0.1m=10cm,
For 54.3km- 0.3m=30cm,
For 91km- 0.5m=50cm.
For 54.3km- 0.3m=30cm,
For 91km- 0.5m=50cm.
RAJ KUMAR said:
8 years ago
IN BC PUNMEA 12KM =1 CM.
BUT IT IS WRONG.
IN ACTUAL 18.5 KM=1CM=10MM.
This is the correct one.
BUT IT IS WRONG.
IN ACTUAL 18.5 KM=1CM=10MM.
This is the correct one.
Ankit said:
8 years ago
I can not understand what is right and what is wrong
Shailendra kumar mahato said:
7 years ago
For distance upto 18.2 km is 10 cm.
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.
Ref: RS Khurmi(clause 5.1).
For distance upto 54.3 km is 30 cm.
For distance upto 91 km is 50 cm.
Ref: RS Khurmi(clause 5.1).
Anil said:
7 years ago
0.1m * 100mm.
100mm * 10cm.
So, 10 cm answer is correct.
100mm * 10cm.
So, 10 cm answer is correct.
Rakesh Kumar Chhalotre said:
7 years ago
12km - 1cm.
So, for 18.2km - 1.5cm = 15mm is correct.
So, for 18.2km - 1.5cm = 15mm is correct.
(1)
Dil said:
7 years ago
18.5km = 1.5cm.
18.2km = 1cm.
18.2km = 1cm.
Joydeep said:
7 years ago
1 cm is the correct answer for 18.2 km.
Sarang patole said:
7 years ago
Correct answer is 1cm.
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