Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 2)
2.
As compared to uniaxial tension or compression, the strain energy stored in bending is only
Discussion:
26 comments Page 2 of 3.
Ajay munde said:
8 years ago
Not getting this. Please explain.
R N yadav said:
8 years ago
Please explain it clearly.
Maneesha.puvvala said:
8 years ago
Can you give me a deep explanation?
Deepak said:
8 years ago
How to solve this? please explain.
Hiralal Singha said:
8 years ago
Not getting this, Explain it please.
Surya said:
8 years ago
Please give the explanation.
Srinivas said:
9 years ago
How it is calculated?
Please explain me.
Please explain me.
Naren said:
9 years ago
Here, [SE] FOR COMPRESSION OR TENSION IS.
= 1/2 * force * deformation.
And what about [SE] for BENDING.
@Dheeraj Hindu.
Could you please explain this one.
= 1/2 * force * deformation.
And what about [SE] for BENDING.
@Dheeraj Hindu.
Could you please explain this one.
Dheeraj hindu said:
9 years ago
We know that,
FOR COMPRESSIOM OR TENSIOIN.
Strain energy(SE) = (1/2) * force * deformation = 1/2) * P * PL/AE = P^2L/2AE.
FOR BENDING.
SE = (P^2L^3)/6AE.
So bending (SE)= (L^2)/3 tension(SE).
FOR COMPRESSIOM OR TENSIOIN.
Strain energy(SE) = (1/2) * force * deformation = 1/2) * P * PL/AE = P^2L/2AE.
FOR BENDING.
SE = (P^2L^3)/6AE.
So bending (SE)= (L^2)/3 tension(SE).
Binit said:
10 years ago
Need more explanation.
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