Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 2)
2.
As compared to uniaxial tension or compression, the strain energy stored in bending is only
Discussion:
26 comments Page 1 of 3.
Samrat said:
1 decade ago
How it is calculated?
Dipankar said:
1 decade ago
Due to middle-third rule.
SUBINSEKHAR said:
1 decade ago
Can you explain?
Syed aasif said:
1 decade ago
We know strain energy stored is direct stress square/2.
Akash said:
1 decade ago
Step 1: Calculate strain energy due to uniaxial loading.
Viz. U1 = {(f^2)xvol}/(2xE).
Step 2: Calculate strain energy due to pure bending.
Viz. U2 = 0.5xMxtheta.
= 0.5x[(fxI)/y]x[(Mxl)/(ExI)].
(from simple bending equation & moment area method resp.)
Solve it U2 = {(f^2)xvol}/(6xE).
i.e U2 = 0.3XU1.
:) :) :) :).
Viz. U1 = {(f^2)xvol}/(2xE).
Step 2: Calculate strain energy due to pure bending.
Viz. U2 = 0.5xMxtheta.
= 0.5x[(fxI)/y]x[(Mxl)/(ExI)].
(from simple bending equation & moment area method resp.)
Solve it U2 = {(f^2)xvol}/(6xE).
i.e U2 = 0.3XU1.
:) :) :) :).
Subhra said:
10 years ago
@Akash,
Please explain me what is l?
Please explain me what is l?
Binit said:
10 years ago
Need more explanation.
Dheeraj hindu said:
9 years ago
We know that,
FOR COMPRESSIOM OR TENSIOIN.
Strain energy(SE) = (1/2) * force * deformation = 1/2) * P * PL/AE = P^2L/2AE.
FOR BENDING.
SE = (P^2L^3)/6AE.
So bending (SE)= (L^2)/3 tension(SE).
FOR COMPRESSIOM OR TENSIOIN.
Strain energy(SE) = (1/2) * force * deformation = 1/2) * P * PL/AE = P^2L/2AE.
FOR BENDING.
SE = (P^2L^3)/6AE.
So bending (SE)= (L^2)/3 tension(SE).
Naren said:
9 years ago
Here, [SE] FOR COMPRESSION OR TENSION IS.
= 1/2 * force * deformation.
And what about [SE] for BENDING.
@Dheeraj Hindu.
Could you please explain this one.
= 1/2 * force * deformation.
And what about [SE] for BENDING.
@Dheeraj Hindu.
Could you please explain this one.
Srinivas said:
9 years ago
How it is calculated?
Please explain me.
Please explain me.
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