Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 2)
2.
As compared to uniaxial tension or compression, the strain energy stored in bending is only
Discussion:
26 comments Page 1 of 3.
Abhishek thakur said:
6 years ago
For(tension and compression):
Due to the stress-strain curve the strain energy;
Resilience = 1/2 * stress * strain.
And proof resilience= 1/2* stress * strain * volume is;
Strain = stress/modulus of elasticity.
Then PR=stress^2*volume/2E.
And for bending moment due to pure axial loading.
M=Wx.
Strain energy due to bending moment = integration of M^2*xdx/2E= integration of (Wx)^2dx/2E (limit 0toL).
Put the value of Moment M here and on solving u will get;
W^2 l^3/6E.
On solving both the value you will get;
1/3.
Due to the stress-strain curve the strain energy;
Resilience = 1/2 * stress * strain.
And proof resilience= 1/2* stress * strain * volume is;
Strain = stress/modulus of elasticity.
Then PR=stress^2*volume/2E.
And for bending moment due to pure axial loading.
M=Wx.
Strain energy due to bending moment = integration of M^2*xdx/2E= integration of (Wx)^2dx/2E (limit 0toL).
Put the value of Moment M here and on solving u will get;
W^2 l^3/6E.
On solving both the value you will get;
1/3.
(10)
Rashmi Jha said:
2 years ago
U= (σ^2*v)/2E.
Where V = area * length
= bL^2 (axial tension) ----> (1)
For bending, strain energy stored by the elemental cylinder is for the entire volume is:
U = Ʃ[ (M^2)/2E ] dx{hear integration from 0 to L}
U = [ (M^2)/2E ]*Ʃ1dx
U = [ (M^2)/2E ]*L.
Now M/I = E/R = σ/y.
So M = σ*I/y.
Putting I = bL^3/12,
(I/Y) = Z = BL^2/6.
U=(σ^2 z/E) =(σ^2*BL^2)/6E ---> (2)
Dividing (2) by (1),
U(bending)=1/3 U(axial).
Where V = area * length
= bL^2 (axial tension) ----> (1)
For bending, strain energy stored by the elemental cylinder is for the entire volume is:
U = Ʃ[ (M^2)/2E ] dx{hear integration from 0 to L}
U = [ (M^2)/2E ]*Ʃ1dx
U = [ (M^2)/2E ]*L.
Now M/I = E/R = σ/y.
So M = σ*I/y.
Putting I = bL^3/12,
(I/Y) = Z = BL^2/6.
U=(σ^2 z/E) =(σ^2*BL^2)/6E ---> (2)
Dividing (2) by (1),
U(bending)=1/3 U(axial).
(7)
Akash said:
1 decade ago
Step 1: Calculate strain energy due to uniaxial loading.
Viz. U1 = {(f^2)xvol}/(2xE).
Step 2: Calculate strain energy due to pure bending.
Viz. U2 = 0.5xMxtheta.
= 0.5x[(fxI)/y]x[(Mxl)/(ExI)].
(from simple bending equation & moment area method resp.)
Solve it U2 = {(f^2)xvol}/(6xE).
i.e U2 = 0.3XU1.
:) :) :) :).
Viz. U1 = {(f^2)xvol}/(2xE).
Step 2: Calculate strain energy due to pure bending.
Viz. U2 = 0.5xMxtheta.
= 0.5x[(fxI)/y]x[(Mxl)/(ExI)].
(from simple bending equation & moment area method resp.)
Solve it U2 = {(f^2)xvol}/(6xE).
i.e U2 = 0.3XU1.
:) :) :) :).
Jeldi said:
8 years ago
U= (σ^2*v)/2E -----> (axial loading)
U=(σ^2*v)/6E -----> (bending)
So ans is (1/3)
For bending
U=Ʃ[ (M^2)/2E ] dx{hear integration frm 0 to L}
U=[ (M^2)/2E ]*Ʃ1dx
U=[ (M^2)/2E ]*L
Now M/I = E/R=σ/y
So M=σ*I/y
On simplifying
U=(σ^2*v)/6E
U=(σ^2*v)/6E -----> (bending)
So ans is (1/3)
For bending
U=Ʃ[ (M^2)/2E ] dx{hear integration frm 0 to L}
U=[ (M^2)/2E ]*Ʃ1dx
U=[ (M^2)/2E ]*L
Now M/I = E/R=σ/y
So M=σ*I/y
On simplifying
U=(σ^2*v)/6E
(1)
Dheeraj hindu said:
9 years ago
We know that,
FOR COMPRESSIOM OR TENSIOIN.
Strain energy(SE) = (1/2) * force * deformation = 1/2) * P * PL/AE = P^2L/2AE.
FOR BENDING.
SE = (P^2L^3)/6AE.
So bending (SE)= (L^2)/3 tension(SE).
FOR COMPRESSIOM OR TENSIOIN.
Strain energy(SE) = (1/2) * force * deformation = 1/2) * P * PL/AE = P^2L/2AE.
FOR BENDING.
SE = (P^2L^3)/6AE.
So bending (SE)= (L^2)/3 tension(SE).
Naren said:
9 years ago
Here, [SE] FOR COMPRESSION OR TENSION IS.
= 1/2 * force * deformation.
And what about [SE] for BENDING.
@Dheeraj Hindu.
Could you please explain this one.
= 1/2 * force * deformation.
And what about [SE] for BENDING.
@Dheeraj Hindu.
Could you please explain this one.
Sarang mote said:
7 years ago
But the strain energy if load multiplied by displacement, Then in case of bending, how do we derive the formula.
(1)
Pawan said:
6 years ago
U= (σ^2*v)/2E -----> (axial loading).
U=(σ^2*v)/6E -----> (bending).
So, answer is (1/3).
U=(σ^2*v)/6E -----> (bending).
So, answer is (1/3).
(4)
Shakil said:
8 years ago
Due to avail stress =σ2/2E.vol.
Due bending = Σ2/6E.vol.
Due bending = Σ2/6E.vol.
(2)
Deepak Kumar said:
2 years ago
I do not understand this.
Please explain this clearly.
Please explain this clearly.
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