Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 25)
25.
While testing a cast iron beam (2.5 cm x 2.5 cm) in section and a metre long simply supported at the ends failed when a 100 kg weight is applied at the centre. The maximum stress induced is :
Discussion:
15 comments Page 1 of 2.
Aja said:
1 decade ago
Can any body explain how it 960kg/cm2 answer came?
Bhavsingh said:
10 years ago
Maximum stress (f) = M/Z.
M = wl/4.
Z = (bd^2)/6.
b = 2.5 cm.
d = 2.5 cm, then f = 960 kg/cm^2.
M = wl/4.
Z = (bd^2)/6.
b = 2.5 cm.
d = 2.5 cm, then f = 960 kg/cm^2.
(1)
Srinu said:
9 years ago
Thank you @Bhavsingh.
Venu said:
9 years ago
What is the L value?
Yesubabu said:
9 years ago
It is m long.
Prabhu said:
8 years ago
The maximum stress (f) = M/Z,
M = WL/4= (100*100)/4=2500 in question a meter is given, it means 1-meter length converted to cm ans is in cm.
Z=bd^2/6=(2.5*2.5^2)/6=2.6042.
f = M/Z=2500/2.6042 = 959.98 nearly equal to 960 kg/cm^2.
M = WL/4= (100*100)/4=2500 in question a meter is given, it means 1-meter length converted to cm ans is in cm.
Z=bd^2/6=(2.5*2.5^2)/6=2.6042.
f = M/Z=2500/2.6042 = 959.98 nearly equal to 960 kg/cm^2.
(4)
Tailam said:
8 years ago
Superb @Prabhu.
(1)
Anil said:
8 years ago
It is not stated that bending or shear stress.
Priya said:
8 years ago
Yes, its not related bending stress.
(1)
Satya said:
7 years ago
Excellent explanation @Prabhu.
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