Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 25)
25.
While testing a cast iron beam (2.5 cm x 2.5 cm) in section and a metre long simply supported at the ends failed when a 100 kg weight is applied at the centre. The maximum stress induced is :
Discussion:
15 comments Page 1 of 2.
Chem said:
4 years ago
Bd 2square/6 is the moment of inertia for square?
Is it not bd^2/12? Please correct me, if I'm wrong.
Is it not bd^2/12? Please correct me, if I'm wrong.
(1)
Tanmoy Ghosh said:
5 years ago
M = WL/4 (100*100)/4 = 2500.
Z = I/Y (bd^2/6) = 2.604.
M/I = F/Y.
F = M/Z (2500/2.604).
F = 960Kg-cm^2.
Z = I/Y (bd^2/6) = 2.604.
M/I = F/Y.
F = M/Z (2500/2.604).
F = 960Kg-cm^2.
(8)
Khait kanwal said:
6 years ago
Good explanation.
(1)
Sarang said:
6 years ago
Asked about maximum but not clearly defined which shear or bending stress. Kinda tough situation:
Shear stress is 1200.
Bending stress is 960.
Shear stress is 1200.
Bending stress is 960.
Ajeet said:
7 years ago
It is also solved by the following method.
qmax=3/2q.avg.
So, qmax=1.5*100/(2.5*2.5).
qmax=3/2q.avg.
So, qmax=1.5*100/(2.5*2.5).
(1)
Satya said:
7 years ago
Excellent explanation @Prabhu.
Priya said:
8 years ago
Yes, its not related bending stress.
(1)
Anil said:
8 years ago
It is not stated that bending or shear stress.
Tailam said:
8 years ago
Superb @Prabhu.
(1)
Prabhu said:
8 years ago
The maximum stress (f) = M/Z,
M = WL/4= (100*100)/4=2500 in question a meter is given, it means 1-meter length converted to cm ans is in cm.
Z=bd^2/6=(2.5*2.5^2)/6=2.6042.
f = M/Z=2500/2.6042 = 959.98 nearly equal to 960 kg/cm^2.
M = WL/4= (100*100)/4=2500 in question a meter is given, it means 1-meter length converted to cm ans is in cm.
Z=bd^2/6=(2.5*2.5^2)/6=2.6042.
f = M/Z=2500/2.6042 = 959.98 nearly equal to 960 kg/cm^2.
(4)
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