Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 8)
8.
The deflection due to couple M at the free end of a cantilever length L is
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

Vetan said:   6 years ago
Slope is ML/EI.
Deflection is ML2/2EI.
(3)

MOUNIKA REDDY said:   1 decade ago
EI(d^2y/dx^2) = M.

(d^2y/dx^2) = M/EI.

dy/dx = (M/EI)*X+C1.

y = (M/2EI)X^2+C1X+C2.

AT X=0, Y=0 SO C2=0.

AT X=0, DY/DX=0 MEANS SLOPE ZERO, SO C1=0.

Y = (M/2EI)X^2 AT X = L.

Y = (M/2EI)L^2.
(1)

L S said:   1 decade ago
IT is ML^3/3EI = Deflection.

ML^2/2EI is Slope.

K.v.u karthik said:   1 decade ago
We have already learnt this in strength of materials subject in second year that too its a basic one simple for cantilever beam. Slope is ML^2/2EI.

Thank you.

Karan said:   10 years ago
Question is not talking about load, it is asking about moment. That's why option C is correct.

Ved said:   10 years ago
By conjugate beam method finding BM for conjugate Beam is equivalent to deflection of desired beam so C is answer.

Lucky said:   8 years ago
The moment equation is m.

Integrate it w.r.t length, we will get slope eq ML.
Again integrate it will get we will get deflection equation ML^2.
So ml^2/EI.

Gaurav said:   7 years ago
Option A is the correct answer.

Uma Shankar said:   6 years ago
Option C is the right answer.

Mrutyunjaya said:   3 years ago
For the cantilever beam.

Slope : Ml^2/2EI
Deflection : Ml^3/3EI
The option C is not correct answer.


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