Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 3)
3.
The ratio of strengths of solid to hollow shafts, both having outside diameter D and hollow having inside diameter D/2, in torsion, is
Discussion:
42 comments Page 4 of 5.
Bharat said:
1 decade ago
Zp(solid)/Zp(hollow) = (pi*D^3/16)/(pi*(D^4-(D/2)^4)/16D) = 16/15.
Parna sengupta said:
1 decade ago
For a hollow shaft whose external diameter is d and internal diameter is d/2, then what will be the polar modulus?
Maggie said:
1 decade ago
The strength of a solid shaft in torsion is given by,
T(solid shaft) = (pi/16)*(max stres)*(D^3).
T(hollow shaft) = (pi/16)*(max stres)*(D^4-d^4)/D.
On solving we get 15/16.
T(solid shaft) = (pi/16)*(max stres)*(D^3).
T(hollow shaft) = (pi/16)*(max stres)*(D^4-d^4)/D.
On solving we get 15/16.
Ajeet said:
1 decade ago
What is diameter of sun and internal and external heat?
AMIT PANDIT said:
10 years ago
For outer diameter (odd) moment of inertia = d^4.
Inner diameter, moment of inertia = (d/2)^4 = (d^4)/16.
For hollow shaft = d^4-(d^4)/16.
= (15/16)d^4.
So, the ratio of hollow shaft is 15/16.
Inner diameter, moment of inertia = (d/2)^4 = (d^4)/16.
For hollow shaft = d^4-(d^4)/16.
= (15/16)d^4.
So, the ratio of hollow shaft is 15/16.
Dwarika prasad sahoo said:
9 years ago
If Solid and Hollow shaft are of the same material and same weight, then Hollow shaft has more strength.
But when outer diameter is same (weight will not be same) then Solid shaft has more strength, so here ratio of the strength of solid and Hollow shaft should be more than 1 as outer diameter same.
But when outer diameter is same (weight will not be same) then Solid shaft has more strength, so here ratio of the strength of solid and Hollow shaft should be more than 1 as outer diameter same.
Shatakshi said:
9 years ago
It's true, ultimately the ratio of Tmax (Solid) / Tmax (Hollow) = D^4/(D^4-d^4).
Let D=20 mm & d=10mm, then D^4=160000 mm^4 & d^4=10000 mm^4.
Therefore, D^4/(D^4-d^4) = 16/15.
Let D=20 mm & d=10mm, then D^4=160000 mm^4 & d^4=10000 mm^4.
Therefore, D^4/(D^4-d^4) = 16/15.
Raghavendra said:
8 years ago
Yeah, the answer must be 16/15.
Krishnavn said:
8 years ago
Here, the answer must be 16/15.
Bhagchand Golhani said:
8 years ago
Zp= π/32(d^4).
So,
Zp(s)/Zp(h)=[π/32d^4]/[π/32*(15d^4)/16],
=16/15.
So,
Zp(s)/Zp(h)=[π/32d^4]/[π/32*(15d^4)/16],
=16/15.
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