Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 1)
1.
A rectangular bar of width b and height h is being used as a cantilever. The loading is in a plane parallel to the side b. The section modulus is
none of these.
Discussion:
45 comments Page 4 of 5.
Loki said:
7 years ago
Loading is parallel to side b then neural axis is perpendicular to side b, I about n.a ( n.a is the axis parallel to bending direction by right-hand thumb rule ) when the plane of loading is symmetry.
Subrata pal said:
7 years ago
Thanks for all the given explanation.
James said:
7 years ago
The correct Answer must be (bd3/12)/(d/2) which means bd2/6.
Star Guy said:
8 years ago
Thanks for explaining in an uderstandable manner @Riyas.
Rehan rufead said:
9 years ago
Section modulus for the rectangular section is 1/6 bd^2. ie I/y.
I = bd^3/12.
Y = d/2 bd^2/6.
Then, how the answer is option C.
I = bd^3/12.
Y = d/2 bd^2/6.
Then, how the answer is option C.
Mukesh yadav said:
1 decade ago
Section modulus = I/Y(max).
Then I = (b^3*h)/12.
And y = b/2.
Then z = (b^2*h)/6.
Then I = (b^3*h)/12.
And y = b/2.
Then z = (b^2*h)/6.
Aaron said:
8 years ago
How y=b/2?
Priya said:
8 years ago
Please explain that when section modulus bh2/6?
Samir sahoo said:
8 years ago
Thank you for the explanation.
RPR said:
8 years ago
Z= (Moment of Inertia )/(Depth of NA).
= (bh3/12)/(h/2)=bh2/6.
= (bh3/12)/(h/2)=bh2/6.
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