Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 1 (Q.No. 1)
1.
A rectangular bar of width b and height h is being used as a cantilever. The loading is in a plane parallel to the side b. The section modulus is
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
45 comments Page 2 of 5.

Ooha said:   1 decade ago
We are using different methods but same concept. So your process is correct no comment.

Rehan rufead said:   9 years ago
Section modulus for the rectangular section is 1/6 bd^2. ie I/y.
I = bd^3/12.
Y = d/2 bd^2/6.

Then, how the answer is option C.

Devendranaik said:   9 years ago
Section modules (z) =I/Y.

MOMENT OF INERTIA (I) =B^3h/12.

Y = b/2.

Therefore = Z = I/Y = B^2h/6.

Aftershock said:   9 years ago
It says parallel to the plan b, that means.

I = bh^3/12.
y = b/2,
Hence Z= b^2h/6.

GHANSHYAM said:   9 years ago
Please explain that what is y and how y = b/2?
And how calculation is z = {(h*b^3/12)/(b/2).

GHANSHYAM said:   9 years ago
What is section module?

Satyendra said:   9 years ago
Section modulus is a geometric property for a given cross-section used in the design of beams or flexural members.

Ummar basha said:   8 years ago
Here, bd^3/12.


Because I xx of rectangular section.

RPR said:   8 years ago
Z= (Moment of Inertia )/(Depth of NA).
= (bh3/12)/(h/2)=bh2/6.

Samir sahoo said:   8 years ago
Thank you for the explanation.


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