Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 3 (Q.No. 14)
14.
For the beam shown in below figure, the maximum positive bending moment is nearly equal to negative bending moment when L1 is equal to
1.0 L
0.7 L
0.5 L
0.35 L.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

PREM ROSHAN said:   2 years ago
For the maximum positive bending moment to be nearly equal to negative bending moment L should be greater than 2L1. So, L1 is less than 0.5L. Therefore the answer is .35L.

ARUN kumar said:   3 years ago
For equal moment L1 = 0.35 L,
For max bending moment is minimum L1 = 0.207 L,
If point load at both ends & for equal deflection condition L1= 0.207L.

ARUN kumar said:   3 years ago
For equal moment L1 = 0.35 L.
For equal deflection L1 = 0.207 L.

Shubham said:   3 years ago
BM at centre = WL1^2/8 + wl1L1^2/2.
Bm at support = WL1^2/2.
WL1^2/8 + wl1L1^2/2 = WL1^2/2.
= 0.207.

Anitha said:   4 years ago
@Kajal.

How come 4a^2?
(1)

Akshay said:   6 years ago
Thanks @Kajal.

Kajal Tomar said:   6 years ago
Correct ans is D; see how.

Max. Positive B.M = W/8 ( L^2 - 4a^2).
Max. Negative B.M = Wa^2 /2.
W/8( L^2 - 4a^2 ) = Wa^2 /2 ( acc. to quest);
Sove nd get a = 0.35 L.
Here (L1 = a = overhang).

Garry said:   6 years ago
Option D is correct the answer will be point 353 times L.

Priya said:   7 years ago
Please describe it briefly.

A. AFARID said:   7 years ago
The corret option D.


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