Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 18)
18.
The B.M. of a cantilever beam shown in below figure at A, is
Discussion:
13 comments Page 1 of 2.
Inayat Ullah Kakar said:
9 months ago
Solution:
The sum of the moment at A =0.
Here;
clockwise +
Anticlockwise -
So,
2×2-4-Ma=0
Ma=0
So the given answer is correct.
The sum of the moment at A =0.
Here;
clockwise +
Anticlockwise -
So,
2×2-4-Ma=0
Ma=0
So the given answer is correct.
(3)
S K Ahmad said:
2 years ago
The unit of the moment at C should be 4Tm, not 4T/m
Raxstar said:
4 years ago
Right, thanks @Farman.
Rahul khan said:
4 years ago
@Lily.
0 is at free end not at fixed end.
0 is at free end not at fixed end.
(1)
Lily said:
4 years ago
@All.
Just remember that B.M at the fixed end is always zero!
Just remember that B.M at the fixed end is always zero!
(1)
Farman said:
5 years ago
Answer is correct, due to the moment at c in the opposite direction, it actually cancels the moment due to point load, and thus net moment is zero.
(1)
Dhiru said:
5 years ago
0 because 4t is resisting moment and question is asking bending moment.
Muhammad Hashim said:
6 years ago
The correct answer is 12 Tm, since the moment from other end also comes to at A due to having single support. Point C is not able to withstand 4 Tm at all.
Dr. Bhagwanjee Jha said:
7 years ago
BM at A = 2 * 2 - 4 = 0.
(1)
Ajay Desai said:
7 years ago
Yes, Right @Deb.
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