Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 15)
15.
The reaction at support A of the beam shown in below figure, is
Discussion:
61 comments Page 6 of 7.
Suraj Patil said:
9 years ago
The answer should be 5T.
Sufyan Parkar said:
9 years ago
First of all, where is A and where is B we can't assume on our own.
Abhishek das said:
9 years ago
Moment will be zero at A.
Rajendhra said:
9 years ago
In simply support the end moments are zero.
DANISH KASSAR said:
9 years ago
Reaction.
Ra + Rb = 1 * 10 = 10..........(1).
Rb * 10 = 10.
Rb = 1.
Put, Rb in above equation then,
Ra = 9.
The moment at A point.
M = 1 * 10 - 1 * 10 = 0.
The moment at A is zero this is answer.
Ra + Rb = 1 * 10 = 10..........(1).
Rb * 10 = 10.
Rb = 1.
Put, Rb in above equation then,
Ra = 9.
The moment at A point.
M = 1 * 10 - 1 * 10 = 0.
The moment at A is zero this is answer.
Siva said:
9 years ago
This problem can be solved by using propped methods.
First find middle support reaction using super imposition principle (compatability eqn) at deflection where the middle support =0.
First find middle support reaction using super imposition principle (compatability eqn) at deflection where the middle support =0.
Srikanth B R said:
9 years ago
No need to calculate simple assumption at any support, the reaction will always be zero.
Vikas said:
8 years ago
It's 1.875 by three moment theorem.
KIRTI said:
8 years ago
Yes, you are correct @Rahul.
Ashar wazir said:
8 years ago
Ra + Rb = 10t
Ra = 10t - Rb,
Therefore to find Ra take moments about A.
Rb = 10t-10t = 0.
Therefore, option A is correct.
Ra = 10t - Rb,
Therefore to find Ra take moments about A.
Rb = 10t-10t = 0.
Therefore, option A is correct.
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