Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 15)
15.
The reaction at support A of the beam shown in below figure, is
Discussion:
61 comments Page 1 of 7.
Mounika reddy said:
1 decade ago
Ray+Rby = 10T.
The distri load convert to pt load 1*5 for 1st member and 1*5 for 2nd.
Take moment about A is zero Rby = 10T.
SO Ray = 0.
The distri load convert to pt load 1*5 for 1st member and 1*5 for 2nd.
Take moment about A is zero Rby = 10T.
SO Ray = 0.
(1)
DIPAK said:
1 decade ago
Above explanation is wrong because R at su = wl/2.
So putting the value in formula so getting answer = 5T.
So putting the value in formula so getting answer = 5T.
Surendra said:
1 decade ago
I think both are you wrong where is Ra in the figure.
Sumit devlekar said:
1 decade ago
According to general assumption Ra is 1st support from left. And answer is (15/8).
Rakesh said:
1 decade ago
I think answer will be 2.5T.
Kishore said:
1 decade ago
This is continuous beam use theorem of three moment to find the reactions at the support.
Sunil said:
10 years ago
Right answer is 2.5 T because in this question A is starting support B is secondary or mid support and is last support. So according to calculation purpose total force are comes on the span AB is 5 and at point a = 2.5 T.
Prakash said:
10 years ago
Where is support A?
Hesan said:
10 years ago
Do not understand support A. B. and C?
Gani said:
10 years ago
Its (3/16)wl at A and C, (5/8)wl at B.
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