Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 2 (Q.No. 15)
15.
The reaction at support A of the beam shown in below figure, is
Discussion:
61 comments Page 5 of 7.
Gani said:
10 years ago
Its (3/16)wl at A and C, (5/8)wl at B.
Krishna said:
9 years ago
Yeah! It's 3/16 wl at A and C and 5/8wl at B.
The correct answer of this problem is not given in the option.
The correct answer of this problem is not given in the option.
Rahul said:
9 years ago
There is Ra, Rb, Rc total load is 1 Ton and distributed in three part (wl/2).
Ra = 2.5 T
Rb = 5 T
Rc = 2.5 T
But in answers it is is not given.
Ra = 2.5 T
Rb = 5 T
Rc = 2.5 T
But in answers it is is not given.
Samm said:
9 years ago
@Gani, you are correct.
Satya said:
9 years ago
According to general assumption, Ra is 1st support from the left. And the answer is 15/8.
Pavan said:
9 years ago
15/8 is the correct answer.
Mohammed yasin said:
8 years ago
Simply moment at pin and roller support is zero, but if you want to how to get its value.
Ray+Rby=1*10,Ray+Rby=10.
Then, take moment at support a,Ma =0,Rby*10-10*5=0, Rby=5
Then, Ray+Rby=10,Ray=5.
Take moment at A,Ma=10*5-Rby * 10,
Ma=10*5-5*10,
Ma=0.
Ray+Rby=1*10,Ray+Rby=10.
Then, take moment at support a,Ma =0,Rby*10-10*5=0, Rby=5
Then, Ray+Rby=10,Ray=5.
Take moment at A,Ma=10*5-Rby * 10,
Ma=10*5-5*10,
Ma=0.
Kishan Singh said:
9 years ago
Answer will definitely Ra = 2.5T.
Saksham said:
9 years ago
You are absolutely correct @Kishan.
Ankush kohli said:
9 years ago
Suppose two spot is A $ B
Vertical reaction,
A+B = 1 * 10 * (10 ÷ 2)
= 50T -------------> 1
Moment of support A
Rb = 1 * 10 * (10 ÷ 2)
= 50
Rb value put on reaction -1
Ra = 0t. $ Rb = 0t.
Vertical reaction,
A+B = 1 * 10 * (10 ÷ 2)
= 50T -------------> 1
Moment of support A
Rb = 1 * 10 * (10 ÷ 2)
= 50
Rb value put on reaction -1
Ra = 0t. $ Rb = 0t.
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