Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 1 (Q.No. 37)
37.
A shaft turning 150 r.p.m. is subjected to a torque of 150 kgm. Horse power transmitted by the shaft is
Discussion:
17 comments Page 2 of 2.
Shiva said:
8 years ago
P = 2πNT/4500.
We get p=31.41,
Which is equal to 10π.
We get p=31.41,
Which is equal to 10π.
Venkatramana g said:
8 years ago
1HP=745.699watts then 2πN/60 x 1/745.699 gives 2πNT/45000 how 4500 comes?
Raghuraj singh chauhan said:
8 years ago
1 horse power = 745.6998 watts, then we find the answer.
Krishna murti said:
8 years ago
How 4500 come? Anybody, Kindly explain it.
Akhilandeshwari said:
9 years ago
P = 2 * φ * N * T/4500,
P = 2 * φ * 150 * 150/4500,
p = 10 *φ.
P = 2 * φ * 150 * 150/4500,
p = 10 *φ.
Monika said:
9 years ago
p = 2nNT/4500.
N = 150 rpm.
T = 150 kgm.
p = 10n.
N = 150 rpm.
T = 150 kgm.
p = 10n.
Bhavsingh said:
10 years ago
p = 2*(py)*n*T/4500.
T = 150 kgm.
n = 150 r.p.m.
p = 10*(py).
T = 150 kgm.
n = 150 r.p.m.
p = 10*(py).
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