Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 3)
3.
A short masonry pillar is 60 cm x 60 cm in cross-section, the core of the pillar is a square whose side is
Discussion:
15 comments Page 1 of 2.
Deepankar said:
4 years ago
Its a sq.colum as its dimensions are equal,
For square column,the shape of kern is also square with diagonal = d/3 = 60/3 = 20cm.
Now the Q asks about the side of the core not the diagonal of the core.
But we know that Area of square=1/2(diagonal)^2.
Also area of sq.=a^2,
Solving these two we get a=diagonal/(underroot of 2).
So a=20/(under root 2)= 14.14cm.
For square column,the shape of kern is also square with diagonal = d/3 = 60/3 = 20cm.
Now the Q asks about the side of the core not the diagonal of the core.
But we know that Area of square=1/2(diagonal)^2.
Also area of sq.=a^2,
Solving these two we get a=diagonal/(underroot of 2).
So a=20/(under root 2)= 14.14cm.
(7)
Neel said:
7 years ago
The shape of the core for the square column is square, not a rhombus.
so, ans is b/6 i.e. 60/3=20.
so, ans is b/6 i.e. 60/3=20.
(2)
Anonymous said:
9 years ago
Side dimension is 60.
So, the distance from center within which if load is applied than column does not go under the tension i.e. b/6 = 60/6 = 10, which give the value 10.
As per right angle tringle, you get the side of core that is 14.14.
So, the distance from center within which if load is applied than column does not go under the tension i.e. b/6 = 60/6 = 10, which give the value 10.
As per right angle tringle, you get the side of core that is 14.14.
(1)
Yogesh said:
9 years ago
For a rectangular column, kernel core is a rhombus with diagonals B/3 & D/3 resp.
In the above Question, dimensions of the core are asked in terms of SIDE.
So, to apply Pythagoras theorem, we must consider a quarter of the rhombus, i.e., a triangle which has the sides B/6 & D/6
So, the side of the rhombus = hypotenuse of the triangle = sq root (10^2 + 10^2) = sq root(200) = 14.14
In the above Question, dimensions of the core are asked in terms of SIDE.
So, to apply Pythagoras theorem, we must consider a quarter of the rhombus, i.e., a triangle which has the sides B/6 & D/6
So, the side of the rhombus = hypotenuse of the triangle = sq root (10^2 + 10^2) = sq root(200) = 14.14
(1)
Umesh said:
9 years ago
Thanks @Yogesh.
(1)
Gopal said:
7 years ago
Kern of a square section is also a square so the sides are b/3 & b/3 hence the answer should be 60/3= 20.
If it is a rectangle of 60x60 then the above-given approach is correct.
If it is a rectangle of 60x60 then the above-given approach is correct.
(1)
Anand said:
7 years ago
The shape of the core in the square section is square and side value is b/3 & d/3 so the answer is 20 cm.
(1)
Sumit said:
7 years ago
Thanks all for explaining.
(1)
Subhankar said:
7 years ago
Here, we can use ((B^2 +D^2)^.5)/6 for calculation.
(1)
Ramya said:
6 years ago
Thank you @Yogesh.
(1)
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