# Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 4 (Q.No. 3)
3.
A short masonry pillar is 60 cm x 60 cm in cross-section, the core of the pillar is a square whose side is
17.32 cm
14.14 cm
20.00 cm
22.36 cm
25.22 cm.
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 1 of 2.

Deepankar said:   3 years ago
Its a sq.colum as its dimensions are equal,

For square column,the shape of kern is also square with diagonal = d/3 = 60/3 = 20cm.
Now the Q asks about the side of the core not the diagonal of the core.

But we know that Area of square=1/2(diagonal)^2.
Also area of sq.=a^2,
Solving these two we get a=diagonal/(underroot of 2).
So a=20/(under root 2)= 14.14cm.
(4)

Ramya said:   5 years ago
Thank you @Yogesh.

Subhankar said:   5 years ago
Here, we can use ((B^2 +D^2)^.5)/6 for calculation.

Sumit said:   5 years ago
Thanks all for explaining.
(1)

Anand said:   5 years ago
The shape of the core in the square section is square and side value is b/3 & d/3 so the answer is 20 cm.
(1)

Gopal said:   6 years ago
Kern of a square section is also a square so the sides are b/3 & b/3 hence the answer should be 60/3= 20.

If it is a rectangle of 60x60 then the above-given approach is correct.
(1)

Neel said:   6 years ago
The shape of the core for the square column is square, not a rhombus.
so, ans is b/6 i.e. 60/3=20.
(2)

Umesh said:   7 years ago
Thanks @Yogesh.
(1)

Yogesh said:   7 years ago
For a rectangular column, kernel core is a rhombus with diagonals B/3 & D/3 resp.

In the above Question, dimensions of the core are asked in terms of SIDE.

So, to apply Pythagoras theorem, we must consider a quarter of the rhombus, i.e., a triangle which has the sides B/6 & D/6

So, the side of the rhombus = hypotenuse of the triangle = sq root (10^2 + 10^2) = sq root(200) = 14.14
(1)

Fgf said:   7 years ago
Can you please explain it step by step?