Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 4 (Q.No. 16)
16.
For keeping the stress wholly compressive the load may be applied on a circular column anywhere within a concentric circle of diameter
d/2
d/3
d/4
d/8
d/10
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

Teja bhopali said:   7 years ago
this rule is called middle fourth rule.

1. For rectangular columns, the kern/core is rhombus( middle third rule).
2. For circular column the kern/core is circular (middle fourth rule).

The eccentricity is D/8. Hence total on either side gives the diameter for the kern.
= D/8 + D/8 = D/4.
(3)

Muhammad Hashim said:   4 years ago
D/8 (circular) on side of the center point.
Total core will be d/8+d/8 = d/4 (middle fourth).

D/6 (rectangular) on one side of center point.
Say total length d/6+d/6=d/3 (middle third).
(2)

B.Singh said:   3 years ago
The load application on a circular column affects stress. If it is under D/4 the stress will be wholly compressive.

D/4 is the Right answer.
(2)

Priya said:   8 years ago
D/8 not correct because d/8 is no tensile condition.

Referance Khurmi Gupta 120page 399 question.

Goutam said:   4 years ago
The core or kernel of the circular cross-section of dia, D is a circle of dia.(d4/d6/d8).

Avi said:   8 years ago
Circular sections of the eccentric- d/8.

A rectangular section of the eccentric- d/6.

Vivek kumar said:   4 years ago
There will be both side d/8+d/8, hence the value of eccentricity in no tension is d/4.

Akscivili@n said:   9 years ago
No, @Satya.

C is the correct answer!

Kameel said:   9 years ago
How is the answer C? Please explain.

Sumit said:   8 years ago
@Akscivilian.

Please explain how?


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