Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 16)
16.
For keeping the stress wholly compressive the load may be applied on a circular column anywhere within a concentric circle of diameter
Discussion:
19 comments Page 1 of 2.
B.Singh said:
3 years ago
The load application on a circular column affects stress. If it is under D/4 the stress will be wholly compressive.
D/4 is the Right answer.
D/4 is the Right answer.
(2)
Vivek kumar said:
4 years ago
There will be both side d/8+d/8, hence the value of eccentricity in no tension is d/4.
Muhammad Hashim said:
4 years ago
D/8 (circular) on side of the center point.
Total core will be d/8+d/8 = d/4 (middle fourth).
D/6 (rectangular) on one side of center point.
Say total length d/6+d/6=d/3 (middle third).
Total core will be d/8+d/8 = d/4 (middle fourth).
D/6 (rectangular) on one side of center point.
Say total length d/6+d/6=d/3 (middle third).
(2)
Goutam said:
4 years ago
The core or kernel of the circular cross-section of dia, D is a circle of dia.(d4/d6/d8).
Netha said:
6 years ago
Superb @Teja.
Sheela KR said:
7 years ago
Thanks @Teja.
Teja bhopali said:
7 years ago
this rule is called middle fourth rule.
1. For rectangular columns, the kern/core is rhombus( middle third rule).
2. For circular column the kern/core is circular (middle fourth rule).
The eccentricity is D/8. Hence total on either side gives the diameter for the kern.
= D/8 + D/8 = D/4.
1. For rectangular columns, the kern/core is rhombus( middle third rule).
2. For circular column the kern/core is circular (middle fourth rule).
The eccentricity is D/8. Hence total on either side gives the diameter for the kern.
= D/8 + D/8 = D/4.
(3)
Santanu said:
8 years ago
e l/8.
Load within l/4.
Load within l/4.
Harsh said:
8 years ago
Diameter = d/8.
Radius = r/4.
Radius = r/4.
Piyush said:
8 years ago
It should be d/8.
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