Civil Engineering - Strength of Materials - Discussion


A simply supported beam carrying a uniformly distributed load over its whole span, is propped at the centre of the span so that the beam is held to the level of the end supports. The reaction of the prop will be

[A]. half the distributed load
[B]. 3/8th the distributed load
[C]. 5/8th the distributed load
[D]. distributed load.
[E]. none of these.

Answer: Option C


No answer description available for this question.

Amro said: (Mar 24, 2016)  
The beam held to the level of end means deflection equals to zero @ med span.

Deflection from distributed load = 5wl^4/384EI (EQ: 1).

Deflection from PROP load = PL^3/48EI (EQ: 2).

From eq1 & eq2.

5wl^4/384EI = PL^3/48EI.

P = 5wl/8.

Mahesh said: (Jul 13, 2017)  
Superb explanation, thanks @Amro.

Hasim Ansary said: (Aug 6, 2017)  
Superb @Amro.

Indu said: (Dec 20, 2017)  
Thanks @Amro.

Narendra said: (Dec 31, 2017)  
Great explanation @Amro.

Rakhi said: (Jan 8, 2018)  
Thank you very much @Amro.

Mukesh said: (Jan 12, 2018)  
Thanks @Amro.

Satya said: (May 18, 2018)  
Thank you Amro.

Srini said: (Aug 1, 2019)  
Thank you for explaining it @Amro.

Abhishek said: (Feb 27, 2020)  
A beam of span l is fixed at one end & simply supported at other end. It carries uniformly distributed load of w per unit run over the whole span. The reaction at the simply supported end is what ?

Mukesh Kumar said: (Apr 1, 2020)  
Ans is 3wl/8.
As at simply supported beam deflection is zero.
Deflection due to distributed load w is wl^4/8EI,
Deflection due to support reaction is pl^3/3EI,
Both are equal so p=3wl/8.

Navneet Kumar said: (Jul 2, 2020)  
No @Mukesh Kumar.

You are using deflection formula of a cantilever beam with UDL but here it is SSB.

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