Discussion :: Strength of Materials - Section 1 (Q.No.38)
|Amro said: (Mar 24, 2016)|
|The beam held to the level of end means deflection equals to zero @ med span.
Deflection from distributed load = 5wl^4/384EI (EQ: 1).
Deflection from PROP load = PL^3/48EI (EQ: 2).
From eq1 & eq2.
5wl^4/384EI = PL^3/48EI.
P = 5wl/8.
|Mahesh said: (Jul 13, 2017)|
|Superb explanation, thanks @Amro.|
|Hasim Ansary said: (Aug 6, 2017)|
|Indu said: (Dec 20, 2017)|
|Narendra said: (Dec 31, 2017)|
|Great explanation @Amro.|
|Rakhi said: (Jan 8, 2018)|
|Thank you very much @Amro.|
|Mukesh said: (Jan 12, 2018)|
|Satya said: (May 18, 2018)|
|Thank you Amro.|
|Srini said: (Aug 1, 2019)|
|Thank you for explaining it @Amro.|
|Abhishek said: (Feb 27, 2020)|
|A beam of span l is fixed at one end & simply supported at other end. It carries uniformly distributed load of w per unit run over the whole span. The reaction at the simply supported end is what ?|
|Mukesh Kumar said: (Apr 1, 2020)|
|Ans is 3wl/8.
As at simply supported beam deflection is zero.
Deflection due to distributed load w is wl^4/8EI,
Deflection due to support reaction is pl^3/3EI,
Both are equal so p=3wl/8.
|Navneet Kumar said: (Jul 2, 2020)|
|No @Mukesh Kumar.
You are using deflection formula of a cantilever beam with UDL but here it is SSB.
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