Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 4 (Q.No. 41)
41.
The section modulus of a rectangular section is proportional to
Discussion:
21 comments Page 1 of 3.
Mian Khan said:
8 months ago
Correct option is (C) product of the area and depth
The section modulus (Z) of a rectangular section is proportional to the product of the area and depth. Here's why:
Z = (b * d²) / 6, A = b * d.
Z = (b * d) * (d/6) = A * (d/6).
This shows that the section modulus (Z) is directly proportional to the area (A) multiplied by the depth (d) divided by 6. Since 6 is a constant, we can say Z is proportional to A * d.
The section modulus (Z) of a rectangular section is proportional to the product of the area and depth. Here's why:
Z = (b * d²) / 6, A = b * d.
Z = (b * d) * (d/6) = A * (d/6).
This shows that the section modulus (Z) is directly proportional to the area (A) multiplied by the depth (d) divided by 6. Since 6 is a constant, we can say Z is proportional to A * d.
(2)
SHubam said:
7 years ago
Correct answer is A. Depending upon the axis which you are taking for calculation whether it is Ix or Iy. Depth & width changes but the area remains same. In simple language,
Ix= product of area n depth.
Iy = product of area n width.
Hence in this question. Axis is not given. So Z will change with the change of I. But area remains same in both the conditions.
Ix= product of area n depth.
Iy = product of area n width.
Hence in this question. Axis is not given. So Z will change with the change of I. But area remains same in both the conditions.
(7)
Prashant said:
6 years ago
In option A, C and D. Area is common and its product with depth and width gives the section modulus, depending upon the axis in consideration. So, AREA is common is all possible options. That's why option A is correct.
(6)
Manojkumar Rajendran said:
3 years ago
They didn't mention section modulus about which axis.
So, it may be about c.g or base or any axis.hence general for z=A.x and z=A.x^2 hence it is proportional to Area. Therefore, Answer A is correct.
So, it may be about c.g or base or any axis.hence general for z=A.x and z=A.x^2 hence it is proportional to Area. Therefore, Answer A is correct.
Nicks said:
6 years ago
If axis changees be Ix or Iy section modules will change.
So, be it bd2/6 or b2d/6. Section modulus will be proportional to 1/6 * area* depth. So C must be the correct answer.
So, be it bd2/6 or b2d/6. Section modulus will be proportional to 1/6 * area* depth. So C must be the correct answer.
(3)
Roshan said:
7 years ago
Z=I/y, I = the second moment of area = Ai*yi.
Z=(Ai*yi)/y.
Z proportional to the summation of the area of the element.
Z=(Ai*yi)/y.
Z proportional to the summation of the area of the element.
Baloch said:
9 years ago
E seems right,
The second moment of area of rectangular sec = bh^3 / 12 , and its Z = bh^2/6 (half).
The second moment of area of rectangular sec = bh^3 / 12 , and its Z = bh^2/6 (half).
Yogesh said:
9 years ago
Z = bd^2/6.
Z ^ bd^2.
Z^(bd) x (d).
Z ^ (Area) x (Depth).
Answer should be 'C'.
Z ^ bd^2.
Z^(bd) x (d).
Z ^ (Area) x (Depth).
Answer should be 'C'.
Jaz said:
6 years ago
Z=I/Y and I=AK^2.
So, that z proportional to area and radius of Gyration.
So, that z proportional to area and radius of Gyration.
Jimmy said:
1 decade ago
How? As per calculation it is A*d/6. Answer should be C.
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