Civil Engineering - Strength of Materials - Discussion

Discussion Forum : Strength of Materials - Section 4 (Q.No. 41)

Strength of Materials

41.

The section modulus of a rectangular section is proportional to

area of the section

square of the area of the section

product of the area and depth

product of the area and width

half moment of inertia of the section.

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

21 comments Page 2 of 3.

Thebaloch said: 8 years ago

S = m/z
Z = M/S
S = F/A

So Z=AM/F.
So, A is correct.

Sehra said: 8 years ago

Z=I/y max=bd^2 /6
Z=Ad/6 A=bit
Z-A or Z- d.

Rakesh kumar sah said: 9 years ago

Section modulus = Z/A.

Hence option A is correct.

Shivkumar said: 7 years ago

You are right @Sumit.

The answer will be A.

Amjad Ali said: 6 years ago

Yes, agree. C is the correct Answer.

(1)

Sonu (Guruji) said: 3 years ago

Agree, the right Answer should be A.

S s said: 9 years ago

You are right @Jimmy, its bd2/6.

RANJAN PATRA said: 9 years ago

Answer should be option C.

Karpi basar said: 2 months ago

Thank you @Shubam.

Suwami said: 9 years ago

Z = I/y = Ak2/y.

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