Civil Engineering - Strength of Materials - Discussion
Discussion Forum : Strength of Materials - Section 3 (Q.No. 10)
10.
For a given material, if E, C, K and m are Young's modulus, shearing modulus, bulk modulus and poisson ratio, the following relation does not hold good
Discussion:
23 comments Page 1 of 3.
Deepak raj joshi said:
1 month ago
The correct relations between elastic constants:
E = 2G(1+u) or E = 2C ( 1 + 1/m).
E = 3k( 1-2u) or E = 3K (1 - 2/m).
E = 9KG/(3K+G) or 9KC/(3K + C).
u = (3K- 2G)/(2G+6K) or 1/m = (3K - 2C)/(2C+6K).
So options B and E are incorrect.
E = 2G(1+u) or E = 2C ( 1 + 1/m).
E = 3k( 1-2u) or E = 3K (1 - 2/m).
E = 9KG/(3K+G) or 9KC/(3K + C).
u = (3K- 2G)/(2G+6K) or 1/m = (3K - 2C)/(2C+6K).
So options B and E are incorrect.
Pratiksha said:
4 years ago
B&E are the correct answer.
Pradeesh said:
5 years ago
Yes, both B & E are correct answer.
Krishan Kumar said:
5 years ago
Yes, both Option B and E are correct.
Naveen said:
5 years ago
B & E is the correct answer. I also agree.
Bhola said:
6 years ago
I too agree it's B and E.
Samar mondal said:
6 years ago
The correct answer is both B & E.
Beenish said:
7 years ago
C option is correct as we know that;
G=E/2(1+u), whereas G=shear modulus and u=poison ratio so it can be written as;
E=2G(1+u) or in this question.
E=2C(1+m) as G=C and u=m.
G=E/2(1+u), whereas G=shear modulus and u=poison ratio so it can be written as;
E=2G(1+u) or in this question.
E=2C(1+m) as G=C and u=m.
Newton Kumar said:
7 years ago
I agree with the given answer.
Amar said:
7 years ago
Good and thanks @Aaqib.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers