Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 5 (Q.No. 43)
43.
A soil sample of mass specific gravity 1.92, has a moisture content 30%. If the specific gravity of solids is 2.75, the void ratio, is
Discussion:
19 comments Page 1 of 2.
Abhay said:
10 years ago
Bulk mass or apparent specific gravity(Gm) = γ/γw = 1.92.
γ= (G+eSr)γw/(1+e) => γ/γw = (G+eSr)/(1+e).
We know, eSr = wG => eSr = 0.3*2.75 = 0.825.
Therefore,
1.92 = (2.75 + 0.825)/(1+e) => 1+e = 3.575/1.92.
Therefore, e = 1.862 - 1 = 0.862.
Note:
γ - The moist unit weight of the material.
γw - Unit weight of water.
G - Specific gravity of a Solid.
e - Void ratio.
Sr - Degree of saturation.
γ= (G+eSr)γw/(1+e) => γ/γw = (G+eSr)/(1+e).
We know, eSr = wG => eSr = 0.3*2.75 = 0.825.
Therefore,
1.92 = (2.75 + 0.825)/(1+e) => 1+e = 3.575/1.92.
Therefore, e = 1.862 - 1 = 0.862.
Note:
γ - The moist unit weight of the material.
γw - Unit weight of water.
G - Specific gravity of a Solid.
e - Void ratio.
Sr - Degree of saturation.
(10)
Rosh said:
10 years ago
Accuracy till 3rd digit.
Krishna said:
9 years ago
Thanks @Abhay.
Sandeep kumar said:
7 years ago
Thanks @Abhay.
Vivek said:
7 years ago
@Abhay.
Why we did not use here relation Gm=G(1-n)?
Why we did not use here relation Gm=G(1-n)?
Amit said:
7 years ago
Gm = G (1- n ) (1+w).
Acc to this relation, the ans is .860.
Acc to this relation, the ans is .860.
(1)
Pavan said:
7 years ago
Thanks @Abhay.
Surabhi said:
6 years ago
@Abhay.
Why can't we use G=Gm(1+e)?
Why can't we use G=Gm(1+e)?
Omi said:
6 years ago
Thanks @Abhay.
Omi said:
6 years ago
G = Gm(1+e) because soil is not dry, Soil contains some water content.
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