Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion
Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
Discussion:
123 comments Page 5 of 13.
Kumar said:
9 years ago
How it will be 70 * (10/25)^.121 = 89.58?
Varsha said:
9 years ago
Interpolation technique is very simple & easily understand to solve this..
Pradeep said:
9 years ago
Moisture content 10 blows 20%.
Moisture content 100 blows 70%.
Answer is 65%.
Moisture content 100 blows 70%.
Answer is 65%.
Harendra said:
9 years ago
According to me, it is 61.70%.
M BADRA said:
9 years ago
By interpolating the value for 25 blows the moisture content will linearly decrease up to 61.7%. Hence my answer is 61.7.
Ritesh said:
9 years ago
According to me,
By using the method of interpolation, my answer is 50.10.
By using the method of interpolation, my answer is 50.10.
Lokesh said:
9 years ago
61.7 is the correct answer, So it is option D.
Siva said:
8 years ago
Why should we take the liquid limit value at 25 blows only? If there any relation, please explain it.
Suman Ghosh said:
8 years ago
Answer 50% is correct.
W = - I log N + C.
W = water content , I = flow index, N= no of blow.
Put value of w & N for both 70% & 20%, then results will be, I=50 & C=120. Now w= -50*log 25 + 120 = 50.1.
W = - I log N + C.
W = water content , I = flow index, N= no of blow.
Put value of w & N for both 70% & 20%, then results will be, I=50 & C=120. Now w= -50*log 25 + 120 = 50.1.
Harshdeep said:
8 years ago
Simply take x= 0.068.
and WL = Wn (N÷25)^x .
WL = 70 (10÷25 )^0.068 = 68.77 approx 65.
and WL = Wn (N÷25)^x .
WL = 70 (10÷25 )^0.068 = 68.77 approx 65.
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