Civil Engineering - Soil Mechanics and Foundation Engineering - Discussion

Discussion Forum : Soil Mechanics and Foundation Engineering - Section 1 (Q.No. 1)
1.
In a liquid limit test, the moisture content at 10 blows was 70% and that at 100 blows was 20%. The liquid limit of the soil, is
35%
50%
65%
none of these.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
123 comments Page 3 of 13.

Apoorv said:   1 decade ago
We can find the flow index 1st using.

I = (w1 - w2)/log(n2/n1) and then find the water content corresponding to the 25 blows using this flow index value.

Ravi Verma said:   1 decade ago
Just simply apply interpolation with 25 blows.

Sagar Shah said:   1 decade ago
If we use flow index than the answer coming is 50. And plot shall be along log scale wouldn't rough idea from that be wrong?

Sharda charan said:   1 decade ago
Given;

n1=10; w1=70%.
n2=100; w2=20%.

Flow index (I)=(w1-w2)/log(n2/n1) = 50;.
wL = Ilog(n2/25)+w2;.
wL = 50.10%.

V RAMESH said:   1 decade ago
Liquid Limit= W * (N/25)^0.121.

where,

W= water content at N blows.
N= no.of blows.

Liquid limit = 70*(10/25)^0121 = 89.55%.
Liquid Limit = 20*(100/25)^0.121 = 23.65%.
required liquid limit = 88-23 = 65%.

Pappu said:   1 decade ago
Liquid limit is define as water content at which the soil possesses an arbitrarily fixed small amount of shear strength.

Mudassir Abbas said:   1 decade ago
Just interpolate it on semi log graph paper. i.e No.of blows on logarithmic x-axis and m.c on y-axis and then find LL along 25 blows.

Ashok said:   1 decade ago
Please anyone explain the proper and simple definition of the liquid limit?

Priya said:   1 decade ago
The arbitrary limit of water content that represents the boundary between the liquid & plastic state is called as liquid limit.

AMAR DEEP TIWARI said:   1 decade ago
Liquid Limit = (20-70)/(100-10) = (LL-70)/(25-10).

So, LL = 61.67%.


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